Answer:
4/5
Step-by-step explanation:
<span>cos x = [ e^(ix) - e^(-ix) ] / 2i along with [ A - B ]^5 =
( A^5 - B^5) - 5 AB ( A^3 - B^3) + 10 A²B² (A - B )...A = e^(ix) , B = e^(-ix)
[ cos x ] ^5 = (1/32i) { [ e^(5ix) - e^(-5x) ] - 5 [ ( e^(3ix) - e^(-3ix) ] + 10 [ e^(ix) - e^(-ix) ] }
= ( 1 / 16 ) { cos 5x - 5 cos 3x + 10 cos x }.....much faster</span>
Any number that is not one over one bit for example 5 over one Is greater than on in whole number form it would be 5 and that is greater
Answer:
The 8 is in the hundredths place.
The 6 is in the thousandths place.
2.586 is equivalent to (2 × 1) + (5 × 0.1) + (8 × 0.01) + (6 × 0.001).
