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Genrish500 [490]
4 years ago
14

Please show your workf

Mathematics
1 answer:
irina [24]4 years ago
7 0
X-2
--------- greater than or equal to 6
2(x+3)

First, clear out the fraction.  Mult. both sides of this inequality by 2(x+3):

x-2 greater than or equal to  6(2)(x+3) 

x-2 greater than or equal to  12x + 36 becomes

-38 greater than or equal to 11x

Thus, -38/11 is greater than or equal to x, or

x is smaller than or equal to -38/11

check:  try x = -44/11 = -4 (this is smaller than -38/11)

Substitute -4 into the original inequality:

x-2
--------- greater than or equal to 6
2(x+3)

becomes

-4-2
--------- greater than or equal to 6
2(-4+3)

or 

-6
---- = 3.  Is this greater than or equal to 6?  No.
-2

So, choose a different test value for x:  Try one that's on the other side of 
-38/11.  I'll try 0.

Then 

0-2
--------- greater than or equal to 6
2(0+3)

-2
---- = -1/3.  Unfortunately, this is not greater than or equal to 6.
6

Thus, this tentative solution fails.


Trying again:

x-2
--------- greater than or equal to 6
2x + 6

Multiply both sides by 2x+6:  x-2 is greater than or equal to 6(2x+6)

Then x-2 is greater than or equal to 12x + 36

Add 2 to both sides:  x is gr. than or = to 12x + 38

Subtr. 38 from both sides:   -38 + x is gr than or equal to 12x, or

-38 is gr than or = to 11x, and -38/11 is gr than or = to x (same as before).

Again, -4 proves NOT to be a solution.  Thus, the interval (-infinity, -38/11) is not part of the solution set.

Trying x = 2,

2-2
------------- comes out to 0, which is NOT greater than or equal to 6.
2(2) + 6

Thus, (-38/11, infinity) is not a solution set either.

NO SOLUTION!

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A square has an area of 9 yd? What is the length of each side?
uranmaximum [27]

Answer:

3 yards

Step-by-step explanation:

The area of a square is its length × width, where the length and width are the same:

length × width = 9

Since, the length and width are the same lets call them x

x × x = 9 → x² = 9

To find x, find the square root of 9:

x² = 9 → x = √9 → The square root of 9 is 3

Each side has a length of 3 yards

3 0
3 years ago
Without using (10), show directly that (10.6^-1)^8=17.6^-8
blagie [28]
We are given the expression:

(17.6^-1)^8 = 17.6 ^ -8

This means that the two terms on each side are equal. We are asked to show how this is possible. 

First, use the rule of exponents. If a term raised to the power of a number x^n and is further raised to the power m: (x^n)^m, to simplify the expression, multiply n and m and this will be your end exponent = x^nm. 

We can apply this rule here:

17.6^-1 ^ 8

-1 * 8 = -8

then, retain the base and replace the exponent with the product nm:

17.6 ^-8. This proves that the left term is equal to the right term. <span />
3 0
3 years ago
What's does 8.84 divided by 0.68 ?
Ray Of Light [21]
8.84/0.68=13 8.84 divided by 0.68 is 13!!!
I hoped I helped(:
6 0
4 years ago
What is the value of -36+(-4/9)
zalisa [80]

- 36 \times 9 =  - 324
-324/9 -4/9
-328/9
5 0
4 years ago
A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}

6 0
3 years ago
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