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Kamila [148]
3 years ago
13

Write a translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 ). I NEED HELPPPP!

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Answer:

T_{ - 5 ,8} \: or \: D'(x,y) →D(x - 5,y + 8)

Step-by-step explanation:

T _ { ? ,?}

D'(x,y) →D(x \pm ?,y \pm ?)

given D : (7,-3), and D' : (2,5)

the coordinates of D can be represented as (x1,y1), and the coordinates of D' can be represented as (x,y).

you can simply take the difference in the x values and difference in the y values from the preimage to image.

like this:

f'(x,y) → f(x+(x-x1),y+(y-y1)) : T _ {(x-x_1),(y-y_1)}

D'(x,y) → D(x+(2-7),y+(5--3))

D'(x,y) → D(x<u>-5</u>,y<u>+8</u>) : T _ {-5 ,8}

xenn [34]3 years ago
3 0

Answer:

5 places to the right on the x-axis and 8 places up.

Step-by-step explanation:

(-5,+8)

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Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216%5C%5C%7D" id="TexFormula1" title="\sqrt[3]{216\\}" alt="\sqrt[3]{216\\}"
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