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3 years ago

Write a translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 ). I NEED HELPPPP!

Mathematics

2 answers:

anzhelika [568]3 years ago

7 0

Answer:

$T_{ - 5 ,8} \: or \: D'(x,y) →D(x - 5,y + 8)$

Step-by-step explanation:

$T _ { ? ,?}$

$D'(x,y) →D(x \pm ?,y \pm ?)$

given D : (7,-3), and D' : (2,5)

the coordinates of D can be represented as (x1,y1), and the coordinates of D' can be represented as (x,y).

you can simply take the difference in the x values and difference in the y values from the preimage to image.

like this:

f'(x,y) → f(x+(x-x1),y+(y-y1)) : $T _ {(x-x_1),(y-y_1)}$

D'(x,y) → D(x+(2-7),y+(5--3))

D'(x,y) → D(x-5,y+8) : $T _ {-5 ,8}$

xenn [34]3 years ago

3 0

Answer:

5 places to the right on the x-axis and 8 places up.

Step-by-step explanation:

(-5,+8)

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At the season finale, you present the winner of Canadian Superstar with a recording-and-tour contract. The contract states that

Zina [86]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Winner is paid :

Monthly pay while on tour = $5000

Pay per CD sold =. $2

A) Equation which relates total earning in terms of number of months 'm' while on tour and the number 'n' of CD's sold.

(Monthly pay * number of months) + (pay per CD * number of CD's)

Earning = 5000m + 2n

B) How much will the winner earn after the first month if 500 CDs are sold?

m = 1, n = 500

5000(1) + 2(500) = $6000

C) Suppose after the third month on tour the new recording artist has earned a total of $74 000. How many GDs were sold?

m = 3

74000 = 5000(3) + 2n

74000 = 15000 + 2n

74000 - 15000 = 2n

59000 = 2n

n = 59000 / 2

n = 29500 CD's

D) In Canada, a record album or CD achieves gold status once it seLls 50 000 units. How much will the artist make if the CD goes gold after 6 months of touring?

n = Gold = 50000 ; m = 6

5000(6) + 2(50000)

30000 + 100000 = 130,000

3 0

3 years ago

Is triangle COW ~ triangle PIG identify the similarity postulate or theorem that applies

ch4aika [34]

We can see that OW/IG = 5/15 = 1/3 and CW/PG = 7/21 = 1/3. So we have two ratios that result in the same value (1/3). We would need to know if CO/IP is also 1/3 as well, so we can use the SSS similarity theorem. However we don't have that information. So we can't use SSS.

Alternatively, if we knew that angle CWO = angle PGI, then we can use the SAS similarity theorem. But that bit of info isn't given to us, so we can't use SAS either.

AA can't be used because we don't know anything about any pairs of angles.

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In short, the answer is choice D. It cannot be determined. There isn't enough information.

4 0

4 years ago

Read 2 more answers

$12.50 for 5 ounces

iragen [17]

Answer:

45 copies per minute

Look at drawing for an explanation

6 0

3 years ago

Average movie prices in the United States are, in general, lower than in other countries. It would cost $78.73 to buy three t

likoan [24]

Average movie ticket cost in Japan = $17.23

Average movie ticket cost in Switzerland = $ 13.52

Step-by-step explanation:

Let x be the cost of movie ticket in Japan and y be the cost of movie ticket in Switzerland.

Given 3 ticket in Japan + 2 tickets in Switzerland = $78.73

⇒ 3x + 2y = 78.73 – – – – (1)

Given 3 ticket in Switzerland + 2 tickets in Japan = $75.02

⇒ 3y + 2x = 75.02

⇒ 2x + 3y = 75.02– – – – – (2)

Now, to solve (1) and (2), we multiply equation (1) by 2 and equation (2) by 3.

(1) × 2 ⇒ 6x + 4y = 157.46 – – – – (3)

(2) × 3 ⇒ 6x + 9y = 225.06 – – – – (4)

Subtract (3) from (4), we get

6x + 9y – (6x + 4y)= 225.06 – 157.46

⇒ 6x + 9y – 6x – 4y= 67.6

⇒ 5y = 67.6

⇒ y = 13.52

Now substitute y = 13.52 in equation (1), we get,

(1) ⇒ 3x + 2(13.52) = 78.73

⇒ 3x = 78.73 – 27.04

⇒ x = 27.23

Hence, Average movie ticket cost in Japan is $27.23

Average movie ticket cost in Switzerland is $ 13.52.

4 0

3 years ago

Complete the square to transform the expression x^2+4x 2 into the form a(x − h)2 + k.

faust18 [17]

Answer:

$(x+2)^2-2$

Step-by-step explanation:

we have the expression

$x^2+4x+2$

Convert to vertex form

$a(x-h)^2+k$

where

a is the leading coefficient

(h,k) is the vertex

Complete the square

$(x^2+4x+2^2)+2-2^2$

$(x^2+4x+2^2)-2$

Rewrite as perfect squares

$(x+2)^2-2$

The coefficient a =1

The vertex is the point (-2,-2)

4 0

4 years ago