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vladimir1956 [14]
3 years ago
14

Gabriella swims 2 laps per minute. What is the rate unit?

Mathematics
1 answer:
fomenos3 years ago
8 0

Answer:

2

Step-by-step explanation:

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In yoshi's garden, 3/4 of the flowers are tulips. Of the tulips, 2/3 are yellow. What fraction of the flowers in Yoshi's garden
choli [55]
First, find the least common multiple of 4 and 3.
LCM=12
So now 3/4=9/12 and 2/3=8/12.
so 8/12 of the tulips are yellow.
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Find the volume of this figure.
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504 and can I get brainliest.

Step-by-step explanation:

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Explain a rule for the pattern: 10, 1, 1/10, 1/100. write the next number.
Pavel [41]
The pattern is that every time it is divided by 10 so the next one would be 1/1000
3 0
3 years ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]
Zina [86]

Answer: Absolute minimum: f(-1) = -2\sqrt{6}

              Absolute maximum: f(\sqrt{12.5}) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = t\sqrt{25-t^{2}}

f'(t) = 1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)

f'(t) = \sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }

f'(t) = \frac{25-2t^{2}}{\sqrt{25-t^{2}} } = 0

For this function to be zero, only denominator must be zero:

25-2t^{2} = 0

t = ±\sqrt{2.5}

\sqrt{25-t^{2}} ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = -\sqrt{2.5} and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = t\sqrt{25-t^{2}}

f(-1) = -1\sqrt{25-(-1)^{2}}

f(-1) = -\sqrt{24}

f(-1) = -2\sqrt{6}

f(\sqrt{12.5}) = \sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}

f(\sqrt{12.5}) = 12.5

f(5) = 5\sqrt{25-5^{2}}

f(5) = 0

Therefore, absolute maximum is f(\sqrt{12.5}) = 12.5 and absolute minimum is

f(-1) = -2\sqrt{6}.

8 0
3 years ago
7
jeyben [28]

Answer:

x = -2

Step-by-step explanation:

Given the point, (-2, 9) and the linear equation of a <u>horizontal line</u>, y = 6:

The linear equation of a horizontal line with a slope of zero (<em>m</em> = 0) is y = <em>b, </em>for which the y-intercept is (0, <em>b</em>). <u>Perpendicular lines</u> comprise of the intersection of two lines forming 90° angles.  

Since we are given the equation of a horizontal line, then we can assume that <em>the line that intersects a horizontal line must be a </em><u><em>vertical line</em></u> in order to form perpendicular lines.

The linear equation of a <u>vertical line</u> with an undefined slope is <em>x</em> = <em>a</em>, for which the x-intercept is (<em>a</em>, 0). Vertical lines have an <u>undefined slope </u>because these lines do not have any horizontal change. Thus, when you try to solve for its slope, the denominator will have a difference of 0, making the mathematical operation undefined.

We can use the <u>x-coordinate</u> of the given point, (-2, 9), to formulate an equation for a vertical line: x = -2.

Therefore, the equation of the line that goes through y = 6 is x = -2.

Attached is a screenshot of the graph of both equations, y = 6 and x = -2, showing that their intersection form 90° angles, making them perpendicular lines.      

8 0
3 years ago
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