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hodyreva [135]
3 years ago
13

N ÷ 10 exponent 2 = 0.123(Help please)

Mathematics
2 answers:
slamgirl [31]3 years ago
7 0

Answer:

n = 12.3

Step-by-step explanation:

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

n = 12.3

Step-by-step explanation:

I'm assuming we're looking for n, to find it, we need to isolate it.

Our equation will be solved through PEMDAS :

Parenthesis

Exponent

Multiply/Divide

Add/Subtract

n / 10^2 = 0.123

Get rid of the exponent by applying it to 10,

10^2 = 100

n/100 = 0.123

Now to get rid of the division, multiply the denominator (100) to both sides.

n/100 * 100 = 0.123 * 100

n = 12.3

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sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
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</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.

<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
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sin(A−B)=sinAcosB−cosAsinB

sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)

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<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
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4 0
4 years ago
Read 2 more answers
One month the store sold 12 electric guitars.If that Was 60% of their sales for the month how many guitars did they sell that mo
Roman55 [17]

Answer:

20 guitars

Step-by-step explanation:

since 12 guitars is equivalent to 60% of the sales then you would divide the 12 guitars by .6 to get the total number of guitars sold

12/.6 = 20 guitars

3 0
3 years ago
Read 2 more answers
Discrete math
nadya68 [22]

Answer:

1) yes

2) No

3) No

4) yes

5) No

Step-by-step explanation:

1) f(0)=0, f(1)=1, f(2)=2, f(3)=3, then f[\{0, 1, 2, 3\}]=\{0, 1, 2, 3\}

2) f(0)=0, 1^2=1\equiv 1 \text{mod 4}, then f(1)=1; 2^2=4\equiv 0 \text{ mod 4}, then f(2)=0; 3^2=9\equiv 1 \text{mod 4}, then f(3)=1

Then f[\{0, 1, 2, 3\}]=\{0, 1, 3\}, this means that f isn't onto.

3.

  • f(0)=0;
  • 1^1-1=0, then f(1)=0
  • 2^2-2=2, then f(2)=2
  • 3^2-3=6\equiv 2 \text{ mod 4}, then f(3)=2

Then  f[\{0, 1, 2, 3\}]=\{0, 2\}, this means that f isn't onto.

4.  f[\{0, 1, 2, 3\}]=\{0, 1, 2,3\}, then f is onto.

5. f[\{0, 1, 2, 3\}]=\{1, 2\}, this means that f isn't onto.

6 0
3 years ago
Help me, i need someone to do this for me, i will give brainliest, five star and a thank you this is worth 100 points!!!!
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Answer:

Step-by-step explanation:

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3 years ago
A) Let X be a random variable that can assume only positive integer values, and assume its probability function is P(X -n) A/3^n
kramer

Answer:

a) The value of A = 2

b) The value of B  = \dfrac{1}{12}

Step-by-step explanation:

a)

Given that:

X should be the random variable that assumes only positive integer values.

The probability function; P[X = n] = \dfrac{A}{3^n} for some constant A and n ≥ 1.

Then, let \sum \limits ^{\infty}_{n =1} P[X =n] = 1

This implies that:

A \sum \limits ^{\infty}_{n =1} \dfrac{1}{3^n}= 1

A \times  \dfrac{\dfrac{1}{3}}{1 - \dfrac{1}{3}} = 1

A \times  \dfrac{\dfrac{1}{3}}{\dfrac{2}{3}} = 1

A \times \dfrac{1}{2}=1

A = 2

Thus, the value of A = 2

b)

Suppose X represents a e constant A (n> 1). Find A.

b) Let X be a continuous random variable that can assume values between 0 and 3

Then, the density function of x is:

f_x(x) = \left \{ {{B(x^2+1)}   \ \ \ 0 \le x \le 3  \ \ \ \atop {0} \ \ \ otherwise} \right.

where; B is constant.

Then, using the property of the probability density function:

\int ^3_0 \ B (x^2+1 ) \ dx = 1\\

Taking the integral, we have:

B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1

B \Big [\dfrac{3^3}{3} +3 \Big ]= 1

B \Big [\dfrac{27}{3} +3 \Big ] = 1

B [ 9 +3 ] = 1

B [ 12 ] = 1

Divide both sides by 12

B  = \dfrac{1}{12}

5 0
3 years ago
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