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3 years ago

Find the range of values of x for which the function defined by f(x)=

Mathematics

1 answer:

maxonik [38]3 years ago

5 0

Answer:

all values! x ∈ R

Step-by-step explanation:

The derivative f'(x) = 6x²-6x+12 is a parabola opening upward, with its (positive!) minimum at (0.5, 11.5). If the derivative is always positive, the function must be increasing everywhere!

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A computer company offers a special discount to college students of 15% off. Find the discounted price of a computer that costs

alexgriva [62]

Answer:

1075.25

Step-by-step explanation:

subtract the 15 percent using freindly percents

6 0

3 years ago

Need the answer for x and y

d1i1m1o1n [39]

Answer:

x = 7°

y = 10°

Step-by-step explanation:

7x = 49

x = 7°

180 = 13y + 1 + 49

combine like terms:

13y = 130

y = 10°

8 0

3 years ago

Read 2 more answers

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

3 0

3 years ago

B is the midpoint of AC. AB = 2x+12 and BC = 5x + 10. Find AC

3241004551 [841]

Answer:

x=6

Step-by-step explanation:

/AB/=2x+12

/BC/=5x+10

3x+2=5x-10 subtract 2 from both sides

3x=5x-12 subtract 5x from both sides

-2x=-12 divide both sides by -2x

x =6

5 0

2 years ago

!!30 points!!<br> Are points A, B, and E collinear or noncollinear?

NeX [460]

A. Noncolinear

ABE although they are in the same side, but they don't lie on the same line.

so its a noncolinear.

7 0

4 years ago