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3 years ago

Solve this plz plz plz plz plz plz plz!

Mathematics

1 answer:

Goshia [24]3 years ago

6 0

Answer is attached with image.

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Answer this question to get marked as brainliest!!!!!

____ [38]

Answer:

Step-by-step explanation:

3 0

2 years ago

The ratio of the longer side of a rectangle to its shorter side is 4 to 3. If the shorter side of the rectangle is 21ft, what is

Eduardwww [97]

Answer:

28 ft

Step-by-step explanation:

Let longer side of rectangle be $L$ and the shorter side be $S$ , thus we can write the ratio:

$\frac{L}{S}=\frac{4}{3}$

Now putting 21 into S, we solve for L:

$\frac{L}{21}=\frac{4}{3}\\3L=4*21\\3L=84\\L=\frac{84}{3}=28$

Hence, length of longer side is 28 ft.

5 0

3 years ago

Read 2 more answers

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

What is the measure of DAE? 45° 46° 91° 146°

Schach [20]

Since BAF is opposite of DAE, they are equal to each other.

134 - 89 = 45

The correct answer is 45

6 0

3 years ago

Read 2 more answers

Jaylan decided she no longer liked the car she was leasing and turned it in 1

Stolb23 [73]

Answer:

Step-by-step explanation:

I'm pretty sure its lease penalty

5 0

3 years ago

Solve this plz plz plz plz plz plz plz!​

Solve this plz plz plz plz plz plz plz!