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melamori03 [73]
3 years ago
11

Solve for r: B=dPIEr^2

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

C

Step-by-step explanation:

So we have the equation:

B=d\pi r^2

And we want to solve for r.

So first, isolate the r variable. Divide both sides by dπ. So:

\frac{B}{d\pi}=\frac{d\pi r^2}{d\pi}

The right side cancels:

\frac{B}{d\pi}=r^2

Take the square root of both sides:

r=\sqrt\frac{B}{d\pi}

We can rearrange the terms:

r=\sqrt\frac{B}{\pi d}

Our answer is C.

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Point C has the coordinates (–1, 4) and point D has the coordinates (2, 0). What is the distance between points C and D?
Luba_88 [7]

We conclude that the distance between points C and D is 5 units.

<h3>How to find the distance between the two points?</h3>

Remember that if we have two points (x₁, y₁) and (x₂, y₂), the distance between these points is:

d = √( (x₂ - x₁)^2 + (y₂ -  y₁)^2)

In this case, we know that:

Point C has the coordinates (-1, 4)

Point D has the coordinates (2, 0)

Then the distance between these two points is:

d = √( (-1 - 2)^2 + (0 - 4)^2) = √25 = 5

We conclude that the distance between points C and D is 5 units.

If you want to learn more about distance between points:

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4 0
2 years ago
Please help me! Thank you!
love history [14]

Answer:

Graph A?

Step-by-step explanation:

Just trying to help, but I don't really know. I would say A because its a HUGE jump, but B is a steady incline, but assuming that A has the little incline in the beginning, and then the jump, then back to the incline, probably A would be more profitable.

7 0
3 years ago
M is the midpoint of CD. Given the coordinates of one endpoint C(10,-5) and the midpoint M(4, 0), find the coordinates of the ot
mash [69]

Answer:

D(-2, 5).

Step-by-step explanation:

We are given that M is the midpoint of CD and that C = (10, -5) and M = (4, 0).

And we want to determine the coordinates of D.

Recall that the midpoint is given by:

\displaystyle M = \left(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2}\right)

Let C(10, -5) be (<em>x</em>₁<em>, y</em>₁) and Point D be (<em>x</em>₂<em>, y</em>₂). The midpoint M is (4, 0). Hence:

\displaystyle (4, 0) = \left(\frac{10+x_2}{2} , \frac{-5+y_2}{2}\right)

This yields two equations:

\displaystyle \frac{x_2 + 10}{2} = 4\text{ and } \frac{y_2 - 5}{2} = 0

Solve for each:

\displaystyle \begin{aligned}x_2 + 10 &= 8 \\ x_2 &= -2 \end{aligned}

And:

\displaystyle \begin{aligned} y_2 -5 &= 0 \\ y_2 &= 5\end{aligned}

In conclusion, Point<em> </em>D = (-2, 5).

5 0
3 years ago
Why does the graph of a function shift left when K is positive and to the right when K is negative?
Sedaia [141]

Answer:

You can visualize this easily.

y=f(x+h)

Now if the argument of the function is taken as (x−h) the value of y will be f((x−h)+h)=f(x)  

The function y acquires the value of f(x) at (x−h) amounting to a left shift.

Hope this makes things clear.

Step-by-step explanation:

3 0
2 years ago
What is the value of i 97 – i?<br> –i<br> 0<br> –2i<br> i Superscript 96
Valentin [98]

<em>The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue</em>

Answer:

i^{97}-i=0

Step-by-step explanation:

<u>Powers of The Imaginary Unit</u>

The imaginary unit i is defined as

i=\sqrt{-1}

The first powers of i are

i^0=1

i^1=i

i^2=(\sqrt{-1})^2=-1

i^3=i.i^2=-i

i^4=i^2.i^2=1

And so on the cycle repeats every four numbers. To find the value of i^{96} we can find the remainder of 96/4=0. So i^{96}=i^0=1

The given expression is

i^{97}-i

Factoring

i(i^{96}-1)

Since i^{96}=1

=i(1-1)=0

The required value is 0

6 0
3 years ago
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