Year 1
$12500 x .07 = $875
12500-875=11625
Year 2
11625 x .07 = $813.75
11625-813.75=10811
Year 3
10811 x .07 = $756.79
10811-756.79= 10054.21
Year 4
10054.21 x .07= 703.79
10054.21-703.79= 9350.42
So after 4 years expect to get $9350.42
Using the binomial distribution, the probabilities are given as follows:
a. 0.2637 = 26.37%.
b. 0.8965 = 89.65%.
c. 0.0148 = 1.48%.
<h3>What is the binomial distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
The values of the parameters for this problem are:
n = 5, p = 0.25.
Item a:
The probability is P(X = 2), hence:
Item b:
The probability is:
In which:
Then:
Item c:
The probability is:
In which:
Then:
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
It's not enough details in your question. But I think I know what you mean. The answer is B. The polygon is equiangular but not equilateral.
Answer: Choice A
g(x) = sqrt(2x)
====================================================
Explanation:
"sqrt(x)" is shorthand for "square root of x"
f(x) = 3x^2 is given
g( f(x) ) = x*sqrt(6) is also given
One way to find the answer is through trial and error. This would only apply of course if we're given a list of multiple choice answers.
------------------
Let's start with choice A
g(x) = sqrt(2x)
g( f(x) ) = sqrt(2 * f(x) ) .... replace every x with f(x)
g( f(x) ) = sqrt(2 * 3x^2 ) .... plug in f(x) = 3x^2
g( f(x) ) = sqrt(6x^2 )
g( f(x) ) = sqrt(x^2 * 6)
g( f(x) ) = sqrt(x^2)*sqrt(6)
g( f(x) ) = x*sqrt(6)
We found the answer on the first try. So we don't need to check the others.
------------------
But let's try choice B to see one where it doesn't work out
g(x) = sqrt(x + 3)
g( f(x) ) = sqrt( f(x) + 3)
g( f(x) ) = sqrt(3x^2 + 3)
and we can't go any further other than maybe to factor 3x^2+3 into 3(x^2+1), but that doesn't help things much to be able to break up the root into anything useful. We can graph y = x*sqrt(6) and y = sqrt(3x^2 + 3) to see they are two different curves, so there's no way they are equivalent expressions.
Answer: none
Step-by-step explanation: