Problem Directions Solve the problem below Follow and complet feet, above ground is given by the quadratic function An object is
thrown vertically upward with an initial velocity of y, feet sec. Its distance S(t) =- 16t² + Vot Find V. so that the highest point the object can reach is 400 feet above ground
The highest point reached by the object refers to the highest or maximum value of the quadratic function which can be determined by solving for k.
k=
From the given quadratic functiom, we get the following values
a=-16
b=Vo
c=0
The highest point reached by the object refers to the highest or maximum value of the quadratic function which can be determined by solving for k.
k=
From the given quadratic functiom, we get the following values
a=-16
b=Vo
c=0
1 answer:
You might be interested in
The length of the arc of the circle with a radius of 2 ft and the angle made at the centre equal to is 10.5ft.
The length of the arc of a circle is equal to the product of the circumference of the circle and the ratio of the angle made by the arc of the circle to 2π. It is given by the formula,
It is given that the radius of the circle is equal to 2 ft while the angle made by the arc at the centre of the circle is equal to . And we know the formula for the length of the arc, therefore, the length of the arc,
Hence, the length of the arc of the circle with a radius of 2 ft and the angle made at the centre equal to is 10.5ft.
Learn more about the Length of the Arc of a Circle: