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sergij07 [2.7K]
3 years ago
9

Find the area of the shaded figure.

Mathematics
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

Its 20

Step-by-step explanation:

Because its correct

pls mark me as brainliest

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Solve the inequality<br><br> 1≥−y/4
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Answer:

y≥-4 or (-4,∞)

Step-by-step explanation:

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3 years ago
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Find the GCF (greatest common factor) of the following terms.<br> {5x2y2,25x3y2,x2y2}
HACTEHA [7]

Answer:

5x2y2 is the GCF common factor of the following terms.

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If line A contains Q(5,1) and is parallel to line MN with M(-2,4) and N(2,1), which ordered pair would be on the perpendicular t
vivado [14]
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.

Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line

y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)

y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)

6 0
3 years ago
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Here are six numbers-4, -2, -1, 5, 6, 8Arrange the card into three pairs with the same total
Usimov [2.4K]

ANSWER 8-4   5-1     6-2

Step-by-step explanation:

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The amount that two groups of students spent on snacks in one day is shown in the dot plots below. Which statements about the me
RUDIKE [14]

Answer:

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Step-by-step explanation:

First, we can find the measures of center for each group.

<u>Group A</u>

Mode: 1

Median: (1 + 2) / 2 = 3 / 2 = 1.5

Mean: (1 * 5 + 2 * 4 + 3) / 10 = (5 + 8 + 3) / 10 = 16 / 10 = 1.6

<u>Group B</u>

Mode: 3

Median: 92 + 3) / 2 = 5 / 2 = 2.5

Mean: (1 * 3 + 2 * 2 + 3 * 4 + 5) / 10 = (3 + 4 + 12 + 5) / 10 = 24 / 10 = 2.4

From here, we can see that...

  • The mean for Group A is less than the mean for Group B.
  • The median for Group A is less than the median for Group B.
  • The mode for Group A is less than the mode for Group B.

Hope this helps!

8 0
3 years ago
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