Based on the given values above, here is the solution to find if how many ants there will be after 10 weeks and 20 weeks.
Since the population increases by 12%. we need to get 12% of the population every week.
500 x .12 = 60.
1st week = 560
2nd week = 627.2
3rd week = 702. 46
4th week = 786.76
5th week = 881. 17
6th week = 986.91
7th week= 1,105.34
8th week= 1,237.98
9th week= 1, 386.54
10th week = 1, 552.92
11th week = 1,739.27
12th week = 1,947.98
13th week= 2,181.74
14th week=2, 443.55
15th week = 2,736.76
16th week = 3, 065. 17
17th week = 3,432.99
18th week= 3,844.95
19th week= 4,306.34
20th week = 4,823.10
Therefore, after 10 weeks, there will be 1,553 ants and after 20 weeks, there will be 4,823 ants.
6x-5=4x+5
+5
6x=4x + 0
-4x
2x=0
x =0
probably to late but whatever
I've never done this type of problem before so I might be wrong but I think the answer is 20420352.25 cm
I just took the circumference (204.2035225) and multipled 100,000 which seems too simple to be right
Answer:
Answer is option 2) pi/3
Step-by-step explanation:
HAVE A NICE DAY!
THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.
Hey There!
First you would need to factor out the two.
-4x^3/2 = -2x^3
2x^2/2= x^2
12x/2= 6x
6/2= 3
Now we have.
-2x^3+x^2+6x+3 / x+1
We would then factor with polynomial division, and then we should have.
-2(2x^2 - 3x - 3)(x+1) / x+1
We would then cancel out the x+1
Therefore, the answer would be 
Hope this helped!
