Help!!!!!!!!!!!! lots of it

Mathematics

1 answer:

Luden [163]3 years ago

4 0

Answer:

Equilateral triangle

Step-by-step explanation:

All the three sides are equal.So, it is equilateral triangle

You might be interested in

How do you solve law of cosine?

Effectus [21]

Draw and label a standard Oblique Triangle, as we’ve done in our previous lessons.

Determine the given congruence, either SAS or SSS, and pick the equation that helps you solve for either a missing side or angle.

Plug into your chosen equation and solve.

The "Law of Cosines" can be used to calculate one side of a triangle when the angle opposite and the other two sides are known. The "Law of Cosines" can be expressed as c2 = a2 + b2 - 2 a b cos C (1)

The cosine rule is an extension of this mathematic principal that makes it effective for non-right triangles and states that in regard to a certain angle, the square of the side of the triangle opposite that angle is equal to the squares of the other two sides added together, minus two times both..

4 0

3 years ago

Read 2 more answers

The profit a company earns every month depends of the amount of product sold, p, for $855 each and the amount spent in rent, uti

3241004551 [841]

Profit = (selling price x number of units) - expenses in this case, the selling price is $855, number of units is 250, and the expenses are $6,780 So, Profit = ($855 x 250) - $6,780 = $206,970 That number times 15% (decimal = 0.15) will be the salary of the CEO So, $206,970 x 0.15 = $31,045.50

SO C.

5 0

3 years ago

The graph of a line and and exponential intersect twice, once, or not at all. Describe the possible number of intersections of e

avanturin [10]

a) A line can intersect a parabola at 2 points, 1 point, or no points respectively. The only possible way at which it intersects at 1 point, would be if it were tangent to the parabola. [Check first attachment]

b) Two different parabolas can intersect at 2 points, 1 point or no points respectively. [Check second attachment]

It is possible for 2 parabolas to intersect at 4 and even 3 points. But one of the parabolas would be on it's side. You can consider those cases.