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2 years ago

What’s this answer ? will give ton of points!!!!!!!!!!

Mathematics

1 answer:

Ann [662]2 years ago

3 0

Answer:

268 cm^2

Step-by-step explanation:

Pink prism:

top: 2 cm * 2 cm = 4 cm^2

right, left, back, front: 4 * 2 cm * 6 cm = 48 cm^2

bottom: completely covered in connection to green prism

Total surface area of pink: 52 cm^2

Green prism:

bottom: 10 cm * 5 cm = 50 cm^2

front, back: 2 * 10 cm * 4 cm = 80 cm^2

right, left: 2 * 5 cm * 4 cm = 40 cm^2

top: 10 cm * 5 cm - 2 cm * 2 cm = 46 cm^2

Total surface area of green: 216 cm^2

Total surface area of composite solid:

52 cm^2 + 216 cm^2 = 268 cm^2

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Answer:

A. 13

Step-by-step explanation:

Note: It seems typo in the question. 5% should read 59.

Let 3 credit courses = x, 4 credit courses = y

As per given we have following equations:

x + y = 18
3x + 4y = 59

Solve the system by elimination. Multiply the first equation by 4 and subtract the second one:

4(x + y) - (3x + 4y) = 4(18) - 59
4x + 4y - 3x - 4y = 72 - 59
x = 13

The answer is 13

Correct choice is A

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3 years ago

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Find the perimeter and area, to the nearest

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Perimeter is equal to 90 in.

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2 years ago

Please help! I just need the second question answered given the first is correct.

Nataliya [291]

Answer: 0.970 ??

Step-by-step explanation:

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3 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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3 years ago

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geniusboy [140]

Answer:

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