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Anon25 [30]
3 years ago
10

Which of the following would have NO association if plotted on a scatterplot?

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
5 0
B because the amount of toys you have and calories you eat do not depend on one another
vfiekz [6]3 years ago
5 0

Answer:

Step-by-step explanation:

BB

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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
In a jewelry store, rings makeup 5/9 of the inventory. Earrings make up 4/15 of the inventory. How many times greater is the rin
Free_Kalibri [48]
First let's make the denominators equal, so that we can compare the two fractions more easily.
To do this, we have to find a number that both 15 and 9 divide into. The smallest number that this can happen to is 45.

15 x 3 = 45
9 x 5 = 45

So we have to multiply 15 by 3 in order to make it into 45. If we're changing the denominator, the numerator must change too, by the same multiplier.

4 ---> 4 x 3 = 12
--
15 ---> 15 x 3 = 45

4/15 = 12/45


5 ---> 5 x 5 = 25
--
9 ---> 9 x 5 = 45

5/9 = 25/45

To find how many times more rings there are, we divide 25 by 12. As the result of this isn't an integer, we leave the answer as a fraction:

There rings inventory is 25/12 times bigger than the earrings inventory.
4 0
3 years ago
Given that 7 x − 2 y = 35 Find y when x = − 9
Sergio [31]

so x = minus 9

then

7 × (-9) - 2y = 35

-63 - 2y = 35

-2y = 35 plus 63

-2y = 98

- y = 49

y = -49

3 0
3 years ago
Read 2 more answers
PLEASE HELP ILL REWARD BRAINLIST
kodGreya [7K]

Answer: (2,1)

Hope it helps <3

7 0
3 years ago
Read 2 more answers
U(-3,6), V(-8, 1), W(-3,1)<br> 180° rotation about the origin
Ad libitum [116K]

Answer:

<em>U'</em>(3, -6), <em>V</em><em>'</em>(8, -1), <em>W</em><em>'</em>(3, -1)

Step-by-step explanation:

According to the <em>180°-rotation rule</em>, you take the OPPOSITE of both the y-coordinate and x-coordinate:

<u>Extended Rotation Rules</u>

270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)

270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)

180°-rotation >> (x, y) → (-x, -y)

I am joyous to assist you anytime.

7 0
3 years ago
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