Answer:

Step-by-step explanation:
The dealing of the cards can be seen in the following way:
We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in  ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in
 ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in  ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in
 ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in  . Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in
. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in  ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in
 ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in  . And again, we have to choose which ones are the hidden ones, which can be chosen in
. And again, we have to choose which ones are the hidden ones, which can be chosen in  ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in
 ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in  ways. And choosing which ones are the hidden ones for this player can be done in
 ways. And choosing which ones are the hidden ones for this player can be done in  ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).
 ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

 
        
             
        
        
        
First let's make the denominators equal, so that we can compare the two fractions more easily.
To do this, we have to find a number that both 15 and 9 divide into. The smallest number that this can happen to is 45.
15 x 3 = 45
9 x 5 = 45
So we have to multiply 15 by 3 in order to make it into 45. If we're changing the denominator, the numerator must change too, by the same multiplier. 
4 ---> 4 x 3 = 12
--
15 ---> 15 x 3 = 45
4/15 = 12/45
5 ---> 5 x 5 = 25
--
9 ---> 9 x 5 = 45
5/9 = 25/45
To find how many times more rings there are, we divide 25 by 12. As the result of this isn't an integer, we leave the answer as a fraction:
There rings inventory is 25/12 times bigger than the earrings inventory.
        
             
        
        
        
Answer:
<em>U'</em>(3, -6), <em>V</em><em>'</em>(8, -1), <em>W</em><em>'</em>(3, -1)
Step-by-step explanation:
According to the <em>180°-rotation rule</em>, you take the OPPOSITE of both the y-coordinate and x-coordinate:
 <u>Extended Rotation Rules</u>
270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x) 
270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
180°-rotation >> (x, y) → (-x, -y)
I am joyous to assist you anytime.