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Maksim231197 [3]
3 years ago
15

Which numbers are a distance of 3 units from 12 on a number line? Solect each correct answer// a. 3 b. 9 c. 15 d. 0 e. -9 f. -15

Mathematics
2 answers:
Sladkaya [172]3 years ago
5 0

Answer:

c. 15 and b. 9

Step-by-step explanation:

It's only 15 because 12+3 is 15. 15 is three steps away from 12 on a number line. The other one would be 9 because it is backwards three from 12 on a number line. 12-3 is 9. So your answers would be 15 and 9 (c and b)

Vesnalui [34]3 years ago
3 0

Answer:

The 3 units from 12 on a number line is 4units

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E Homework: 3.1 Homework
LenKa [72]

The given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

The given function is f(z)=3z-8.

We need to find the value of f(-4), f(2), f(z-7).

<h3>What is a function?</h3>

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

Now to find f(-4), replace z from -4.

f(-4)=3(-4)-8=-12-8=-20

Now to find f(2), replace z from 2.

f(2)=3(2)-8=6-8=-2

Now to find f(z-7), replace z from z-7.

f(z-7)=3(z-7)-8=3z-21-8=3z-29.

Therefore, the given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

To learn more about functions visit:

brainly.com/question/21145944.

#SPJ1

4 0
2 years ago
The graph below shows the relationship between time and distance traveled by a race car moving at a
wel

Answer:

It takes 2.4 hours to travel 480 miles.

Step-by-step explanation:

From the graph race car is moving at 100 miles in 0.5 hours. So, in 1 hour, car could travel 2*100 =200 miles per hour.

So, we can set up equation as

y= 200x.

Plug in y as 480 then solve for x.

480 =200x

Divide both sides by 200

2.4=x

So, it would take 2.4 hours.

4 0
3 years ago
Mr.kendall will build a dollhouse bed as a scale model of an actual bed. The actual bed is 40 inches wide and 78ninves long. The
NISA [10]
The answer would be 64
7 0
3 years ago
Give you the brainlest if can just can with me
Komok [63]
This makes no sense but that would be fire
5 0
3 years ago
Read 2 more answers
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
avanturin [10]
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900

There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20

The price of an advance ticket was 20.
The price of a same-day ticket was 15.
6 0
4 years ago
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