Let's solve your equation step-by-step.<span>8=<span>8f
</span></span>Step 1: Flip the equation.<span><span>8f</span>=8
</span>Step 2: Divide both sides by 8.<span><span><span>8f/</span>8/</span><span>8/8
</span></span><span>f=1
</span>Answer: f=1
Hope this helped you :)
Answer:
(2 , 3)
Step-by-step explanation:
Lines intersection is the solution
Answer:
The triangle should be 16 inches wide.
Step-by-step explanation:
![\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2](https://tex.z-dn.net/?f=%5Ctext%20%7BUse%20the%20Pythagorean%20Theorem%20to%20solve%20for%20the%20leg.%7D%5C%5Ca%5E2%20%2B%20b%5E2%20%3Dc%5E2)
What we know:
- One of the legs measures 12 inches.
- The hypotenuse is 20 inches.
We need to solve for b. Solving for a while b is 12 would also be acceptable.
![12^2 + b^2 = 20^2 \text { OR } a^2 +12^2=20^2](https://tex.z-dn.net/?f=12%5E2%20%2B%20b%5E2%20%3D%2020%5E2%20%20%5Ctext%20%7B%20%20OR%20%20%7D%20%20%20a%5E2%20%2B12%5E2%3D20%5E2)
We will use the first equation.
![12^2 + b^2 = 20^2\\12 * 12 = 144\\20 * 20 = 400\\\\\boxed {144 + b^2 = 400}](https://tex.z-dn.net/?f=12%5E2%20%2B%20b%5E2%20%3D%2020%5E2%5C%5C12%20%2A%2012%20%3D%20144%5C%5C20%20%2A%2020%20%3D%20400%5C%5C%5C%5C%5Cboxed%20%7B144%20%2B%20b%5E2%20%3D%20400%7D)
![\text {Subtraction property of equality: }\\144-144+ b^2 = 400-144\\\boxed {b^2 = 256}\\\\\text {Take the square root of 256: }\\\sqrt{256}=\sqrt{b^2} \boxed {16 = b}](https://tex.z-dn.net/?f=%5Ctext%20%7BSubtraction%20property%20of%20equality%3A%20%7D%5C%5C144-144%2B%20b%5E2%20%3D%20400-144%5C%5C%5Cboxed%20%7Bb%5E2%20%3D%20256%7D%5C%5C%5C%5C%5Ctext%20%7BTake%20the%20square%20root%20of%20256%3A%20%7D%5C%5C%5Csqrt%7B256%7D%3D%5Csqrt%7Bb%5E2%7D%20%5Cboxed%20%7B16%20%3D%20b%7D)
The triangle should be 16 inches wide.
R'S' = RS x 3/4
R'S' = 8 x 3/4 = 6 units
S'T' = ST x 3/4
S'T' = 10 x 3/4 = 7.5 units
Answer:
![\frac{3x+4y^2}{3x+y^3}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%2B4y%5E2%7D%7B3x%2By%5E3%7D)
Step-by-step explanation:
Given
← factor numerator/ denominator
=
← cancel 2x² on numerator/ denominator
= ![\frac{3x+4y^2}{3x+y^3}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%2B4y%5E2%7D%7B3x%2By%5E3%7D)