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Lelechka [254]
3 years ago
10

= Given g(x) = -x +4, solve for x when g(x) = -3.

Mathematics
2 answers:
Gemiola [76]3 years ago
6 0

Answer:

x=-7 i guess

Step-by-step explanation:

Aloiza [94]3 years ago
4 0

9514 1404 393

Answer:

  x = 7

Step-by-step explanation:

Put -3 where g(x) is and solve the resulting equation for x.

  g(x) = -x +4

  -3 = -x +4

  x -3 = 4 . . . . . . add x (so we can work with a positive coefficient

  x = 7 . . . . . . . . add 3

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Step-by-step explanation:

Given equation:

\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1

Add the numerators and keep the denominator so that there is now one fraction:

\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1

Simplify the numerator by expanding the brackets:

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