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sattari [20]
3 years ago
5

Helen had to read 148 pages of her science textbook in the 4 days remaining before an exam. If she reads the same number of page

s each day, how many pages will she need to read each day
Mathematics
1 answer:
AfilCa [17]3 years ago
4 0
The answer is 37.......
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Mrs. Walters gets 14.4 miles per gallon.
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360/25=14.4 480/32=15
Stephen can read 90 pages in 6 days witch means he reads 15 pages per day. Which means it will take him 20 days to read a 300 page book.

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3 years ago
Please Help Fast Algebra 1
Ostrovityanka [42]

Answer:

it's answer is C. 1

Step-by-step explanation:

Given

f(x) = -2x + 7

f(3) = - 2 * 3 + 7

= - 6 + 7

= 1

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3 years ago
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Answer:

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3 years ago
En la ruta que un automovilista recorre para trasladarse a su trabajo existen dos intersecciones con señalamientos de tránsito.
wolverine [178]

Answer:

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Step-by-step explanation:

3 0
2 years ago
Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

3 0
3 years ago
Read 2 more answers
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