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jasenka [17]
3 years ago
10

If there are 1000 grams in a kilogram and 454 grams in a pound, how many pounds are there per kilogram?

Mathematics
2 answers:
monitta3 years ago
7 0
Per kg, there would be 2.20462 pounds but you can round it
irina1246 [14]3 years ago
7 0

Answer:2.2 pounds per kilogram

Step-by-step explanation:

454gram = 1 pound

since; 1000g = 1kg

454g = x

x= 454/1000

x=0.454kg

there is 0.454kg in 1 pound

but the question says how many pound is in 1kg

0.454kg = 1 pound

1 kg = x

cross multiply

0.454x = 1

Divide bothside by 0.454

x = 1/0.454

x = 2.2 pound

Therefore; there are 2.2pounds in 1 kilogram.

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Write the equation of a line passing through -1,4 and perpendicular to x+2y=11
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Y=2x+6
gradient is found from the formula,
\frac{ - 1}{ -  \frac{1}{2} }  = 2
y intercept is found by subbing the values of (-1,4) into the equation y=2x+c
8 0
3 years ago
What is the factor of 18x4-14x3+10x2?<br> how do you solve it po?, medyo confused lang
neonofarm [45]

Please find attached photograph for your answer.

8 0
2 years ago
The number of views on an interesting video after it's uploaded is represented by the following table:
defon

Answer:

The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data is ,V(t)=50(6.25)^t

Step-by-step explanation:

Time (months)         Views

0                                  50

2                                  313

4                                  1950

6                                  12,210

8                                  76,300

10                                 476,800

(x_1,y_1)=(0,50)\\(x_2,y_2)=(2,313)\\(x_3,y_3)=(4,1950)

Slope = \frac{y_2-y_1}{x_2-x_1}

Slope = \frac{313-50}{2-0}

Slope =131.5

Slope = \frac{y_3-y_2}{x_3-x_2}

Slope = \frac{1950-313}{4-2}

Slope =818.5

Since the slope is not same . So, it is not a linear relationship

\frac{y_2}{y_1}=\frac{313}{50}=6.25\\\frac{y_3}{y_2}=\frac{1950}{313}=6.25

Since the ratio between the consecutive outputs is same so, it is exponential relationship.

Formula : y=ab^t

Where a is the initial value = 50

b = rate of change = 6.25

The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data

So,V(t)=50(6.25)^t

5 0
2 years ago
 Van purchased a DVD player on sale. The original selling price was ​$175.80. The sale price was ​$149.42. What is the first ste
rjkz [21]

Answer:

The percent decrease was 15%

Step-by-step explanation:

In order to find this, use the percent change equation.  

(New - Old)/(Old) * 100 = % Change

Now input 149.42 for the New price and 175.80 for the Old price.  

(149.42 - 175.80)/(175.80) * 100 = % Change

-26.38/175.80 * 100 = % Change

-.15 * 100 = % Change

-15 = % Change

5 0
3 years ago
Consider the figure.<br> What is JL?
lisov135 [29]

The answer for the above mentioned problem is JL = 12.5

Step by step explanation:

Given:

JM = 8

KM = 6

To Find:

JL = ?

Formula to be used:

KM^2 = JM x ML

In order to find " JL" we must first find "ML",

KM^2 = JM x ML

         6^2 = 8 x ML

         36 = 8 x ML

         36/8 = ML

         ML = 4.5

Now JL = 4.5+8

             = 12.5

Thus the value of JL = 12.5

3 0
3 years ago
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