Answer:
Explanation:
We were given the function:
Discontinuity occurs when the denominator equals zero
When x = -4, the value of the denominator is zero
Removable discontinuity occurs when both the numerator and denominator are zero
We will check this by inputting x = -4 in the expression, we have:
Thus, when x = -4, we have a removable discontinuity
Hence, our answer is: (x, y) = (-4, 0)
Answer:
Step-by-step explanation:
-y = -5x + 7
y = 5x - 7
perp.: -1/5
y - 2 = -1/5(x + 8)
y - 10/5 = -1/5x - 8/5
y = -1/5x + 2/5
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Formula
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Area of circle = πr²
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Find radius
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πr² = 75
r² = 75 ÷ π
r² = 23.87
r = √23.87
r = 4.89 cm (nearest hundreds)
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Answer : radius = 4.89cm
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First find the the value of t where the curve intersects the Y-axis. This is when x = 0.
x = t^2 - 2t = 0 = t(t - 2)
So t= 0 and t = 2
dA = (0 - x)*dy .... Since the curve has negative x in this region
y = SQRT(t) and dy = [(1/2)/SQRT(t)]dt
dA = [2t - t^2][(1/2)/SQRT(t)]dt
dA = [t^(1/2) - (1/2)t^(3/2)]dt
Integrate to get: A = (2/3)t^(3/2) - (1/5)t^(5/2)
Now evaluate from t= 0 to t = 2.
Area = [(2/3)2^(3/2) - (1/5)2^(5/2)] - [0]
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Area = SQRT(2)[4/3 - 4/5]
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Area = SQRT(2)[8/15) = 0.754
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