Answer:
Step-by-step explanation:
The set up is a right angles triangle where;
Height of the building = 30feet (opposite)
Angle of elevation = 70 degrees
Length of the ladder (hypotenuse) = x
Using SOH trig identity;
sin theta = opp/hyp
sin 70 = 30/x
x = 30/sin 70
x = 30/0.9397
x = 31.93feet
Hence the ladder must be 31.93 feet long to reach the top of the building
Answer:
A is correct
Step-by-step explanation:
RP is 3 units long and its transformation R'P' is 1 unit long
R'P' = 1/3 * RP
so the scale factor is 1/3
16/8 =2
24/8 =3
8 packets
each packet will have 2 pencils and 3 erasers
Answer: 12 h ; 45 m
Step-by-step explanation:
*Important: From what I can see in this image, this appears to be a test. If this is the case, please do not cheat. In any case, here is the explanation.
What we know:
- Progress has been made to 4.75
- Rate of digging is 3/5 mph
- Depth must be at least 12 1/2
- We need to find the minimum amount of time the machine works
How to solve:
By setting up an algebraic equation, we can solve this.
Process:
- Set up equation 4.75 + 3/5x = 12 1/2
- Convert 19/4 + 3/5x = 12 1/2
95/20 + 12/20x = 250/20
12/20x= 155/20
- Isolate x via division /(12/20) /(12/20)
- +Simplify
x= 12 11/20
Solution: 12 ; 45