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Hitman42 [59]
2 years ago
7

Riski states that any function written without exponents must be linear.Which function proves Riski 's statement is incorrect? A

)y=5x+3 B)y=x⁵+3 C)y=×/3+5 D)y=3/×+5​

Mathematics
1 answer:
erik [133]2 years ago
7 0

Answer:

D

Step-by-step explanation:

Riski states that any function written without a exponent must be linear ( straight) however the equation y= 3/x+5 shows a non-linear line when graphed.

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Need help with a math question
irina1246 [14]

Answer: 27

Step-by-step explanation:

No. Of juniors: 8

Total students: 30

8/30 x 100 = 26.66

Rounds to (whole percent): 27

6 0
3 years ago
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Two brothers are saving money to buy tickets to a concert. their combined saving is $55 one brother has $15 more than the other.
Vladimir [108]

Brother one: x

Brother two: x + 15

---

Make them add up to 55 in an equation.

x + (x + 15) = 55

Combine like terms.

2x + 15 = 55

Subtract 15 from both sides.

2x = 40

Divide both sides by 2.

x = 20

Plug 20 for x into brother two.

(20) + 15 = 35

Brother one has saved $20, brother two has saved $35.

6 0
3 years ago
Write 37 99 as a decimal. A) 0.037 B) 0.37 C) 0.37 D) 3.73 (ALSO there are 2 of the .37 in the problem so im not sure what i hav
Anastaziya [24]

Answer:

Step 1: Address input parameters & values.

Input parameters & values:

The fraction number = 37/99

Step 2: Write it as a decimal

37/99 = 0.3737

0.3737 is the decimal representation for 37/99

Answer is 0.3737 repeating.

Hope this helps! Plz mark brainliest! ☜(゚ヮ゚☜)

4 0
3 years ago
Can u help me with this
NISA [10]
9.7 x 4.658 = 45.1826

hope it helps
...................
7 0
3 years ago
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The midpoint of segment QR is M(-2, 9). One end point of segment QR is Q(-8, 12). Find the coordinates of the other endpoint, R.
DanielleElmas [232]

Here,

The midpoint of segment QR is M

<u>m</u><u>(</u><u>-2</u><u>,</u><u>9</u><u>)</u> x3=-2,y3=9

<u>Q</u><u>=</u><u>(</u><u>-8</u><u>,</u><u>1</u><u>2</u><u>)</u>x1=-8,y1=12

R=x2,y2

we know that,

\tt{ m=\dfrac{Q+R}{2} } ⠀

So,

x3=\tt{\dfrac{x1+x2}{2} } ⠀

\tt{-2=\dfrac{-8+x2}{2}  } ⠀

\tt{-2×2=-8+x2  } ⠀

\tt{x2=8-4  } ⠀

\tt{x2=4  } ⠀

x2=4

now we find the y coordinate y2.

y3=\tt{\dfrac{y1+y2}{2} } ⠀

\tt{9=\dfrac{12+y2}{2}  } ⠀

\tt{9×2=12+y2  } ⠀

\tt{y2=18-12  } ⠀

\tt{y2=6  } ⠀

y2=6

<em>Now</em><em> </em><em>we</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>coordinate</em><em> </em><em>of</em><em> </em><em>R</em>

<em>so</em><em>,</em>

R=(x2,y2)=(4,6)

7 0
2 years ago
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