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fredd [130]
3 years ago
7

Estimate the isoelectric point of a ser–his dipeptide. explain why this value is only an estimate.

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0
A dipeptide bond connects two amino acids. Ser stands for Serine while His stands for Histidine. Isoelectric point is when all charges of the two amino acids cancel out. This can be estimated by finding the average of the isoelectric points (pI) of the two amino acids.

Serine: pI = 5.68
Histidine: pI = 7.59

Average pI = (5.68 + 7.59)/2 =<em> 6.635

</em>
<em />This is only a rough estimate because an arithmetic average will not coincide with the biochemistry of the amino acids. The true value of the isolectric point is determined through experimentation. However, it would be more ore less around 6.635.<em>
</em>
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Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

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The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

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To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

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Leviafan [203]
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