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marysya [2.9K]
3 years ago
13

Which expressions represent 94 increased by twice a number​

Mathematics
1 answer:
Rufina [12.5K]3 years ago
8 0

Answer:

2x+94

Step-by-step explanation:

because 2x means 2×x +94

x= unknown number

+=increase

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Match each question to the correct problem.
Maslowich
<h2>Answer:</h2>

<em>(Check attached images).</em>

<h2>Step-by-step explanation:</h2>

<h3>Exercise 1.</h3>

a. Convert to decimals.

To order the numbers from least to greaters, convert them to decimals and compare.

5.2(percent)=0.052\\ \\\frac{1}{7} =0.1429\\\\ -0.8=-0.8000\\ \\\frac{-11}{5} =-2.2

b. Select the second least number.

-0.8.

<h3>Exercise 2.</h3>

a. Convert to decimals.

-3.4(percent)=-0.034\\ \\-0.031\\\\ -0.2\\ \\-\sqrt{0.8}= -0.8944

b. Select the correct number.

-\frac{1}{5}.

<h3>Exercise 3.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

<em>59%=0.59</em>

<em>3/5=0.6</em>

<em />

b. Select the correct number.

3/5.

<h3>Exercise 4.</h3>

a. Convert to decimals.

-0.35

-3.5%= -0.035

b. Conclude.

Seeing that -3.5% is less than -0.35, the symbol that makes the statement true is ">".

<h3>Exercise 5.</h3>

a. Try to visually estimate b.

B appears to have a value of -0.9.

b. Convert the numbers to decimals.

-3.4%= -0.034

-0.031

-1/5= -0.2

-\sqrt{0.8}= -0.8944

c. Select the correct answer.

<em>Since we estimated the value of b as -0.9, the number that best adequates to its value is </em>-\sqrt{0.8}.

<h3>Exercise 6.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

5.2%= 0.052

1/7= 0.1429

b. Select the correct number.

5.2% is the second largest.

<h3>Exercise 7.</h3>

a. Convert to decimals.

6/7= 0.857143

0.857

b. Select the correct answer.

Seeing that 0.857 is marked as an approximate by the

ellipsis,  and considering that 6/7 is an irrational numbers, we can conclude that the number that better fits the situation and makes the statement true is "=".

<h3>Exercise 8.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the negative numbers.</em>

<em>-4.6</em>

<em />-\sqrt{21} =-4.5826

b. Select the correct answer.

The smallest number is -4.6.

7 0
2 years ago
in the six grade 54% of the are boys. there are 189 boys in the sixth grade. what is the total number of the students in sixth g
notka56 [123]

<h2>189 boys is 54%</h2><h2>x is 46%(100-54)</h2><h2>Cross multiply:</h2><h2>189*46%=54%*x</h2><h2>86.94=0.54x</h2><h2>x=161</h2><h2>189 boys 161 girls</h2><h2>350 altogether</h2><h2>Hope this helps plz hit the crown :D</h2>
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3 years ago
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Step-by-step explanation:

Im trying to get pts

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Answer:

i think so what is aap name

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A professor has been teaching accounting for over 20 years. From her experience she knows that 75% of her students do homework r
Nata [24]

Answer:

a) P(B|A) =\frac{P(A and B)}{P(A)}=\frac{0.65}{0.75}=0.867

b) In order to two events can be considered as independent we need to have this condition:

P(A and B) = P(A)*P(B)

If we check the condition we see this:

P(A)*P(B)= 0.75*0.7=0.525 \neq P(A and B)

So since we don't have the condition satisfied the events "do the homework regularly" and "pass the course" are not independent.

Other way to check independence is with the following two conditions:

P(B|A)=P(B) or P(A|B)=P(A), and we see that P(B|A)\neq P(B)  for our case.

Step-by-step explanation:

Data given

Lets define the following events

A: Represent the students who do homework regularly

B: Represent the students who  pass the course

75% of her students do homework regularly

70% of her students pass the course

65% of her students do homework and also pass the course

For this case we have some probabilities given:

P(A) =0.75, P(B) =0.70 and P(A and B)=0.65

Solution to the problem

Part a

On this case we want to find this probability:

P(B|A) the conditional probability (Pass the course given that he does the homework regularly).

By defintion of conditional probability we know that:

P(B|A) =\frac{P(A and B)}{P(A)}

And now we can replace in the conditional formula like this:

P(B|A) =\frac{P(A and B)}{P(A)}=\frac{0.65}{0.75}=0.867

Part b

In order to two events can be considered as independent we need to have this condition:

P(A and B) = P(A)*P(B)

If we check the condition we see this:

P(A)*P(B)= 0.75*0.7=0.525 \neq P(A and B)

So since we don't have the condition satisfied the events "do the homework regularly" and "pass the course" are not independent.

Other way to check independence is with the following two conditions:

P(B|A)=P(B) or P(A|B)=P(A), and we see that P(B|A)\neq P(B)  for our case.

6 0
3 years ago
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