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ludmilkaskok [199]
3 years ago
14

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!

Mathematics
2 answers:
mihalych1998 [28]3 years ago
6 0
<h3>Answer:  C) 98</h3>

=============================================================

Explanation:

Let x be the next test grade. It ranges from 0 to 100, inclusive of both endpoints.

The original set {87,92,90,84,88,91} becomes {87,92,90,84,88,91,x} after adding on that score.

We have 7 scores now. We find the average by adding up those seven scores and dividing by 7.

average = (sum of the scores)/(number of scores)

average = (87+92+90+84+88+91+x)/7

average = (532+x)/7

We want the average to be 90 or higher, so we would then have these steps

\text{average} \ge 90\\\\\frac{532+x}{7} \ge 90\\\\532+x \ge 90*7\\\\532+x \ge 630\\\\x \ge 630-532\\\\x \ge 98\\\\

This means Edgar must score a 98 or higher on the seventh test in order for his overall average to be 90 or higher.

In other words, the lowest test score he can get is a 98.

------------------

Extra info (optional section):

Let's say Edgar gets the highest score possible.

So he gets x = 100

This would mean

average = (87+92+90+84+88+91+x)/7

average = (532+x)/7

average = (532+100)/7

average = 632/7

average = 90.2857 which is approximate

We can see that his overall average would stick to 90 if the teacher is rounding to the nearest whole number.

devlian [24]3 years ago
3 0

Answer:

C. 98

Step-by-step explanation:

If you add all of his previous test scores and go through the list of numbers you get C.98 as the answer. I added all of his test scores plus 98 which equals 630 divided by 7 (because if he got a 98 there would be 7 test scores) you would get 90 or an A average.

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A rectangle has a width of 4.2 m and an area of 37.8 m^2

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