1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gizmo_the_mogwai [7]
3 years ago
8

Expanded form for 3,029,251

Mathematics
2 answers:
aliina [53]3 years ago
8 0
Try this : <span>3x10^6 + 2x10^4 + 9x10^3 + 2x10^2 + 5x10 + 1</span>
Arisa [49]3 years ago
5 0
3,000,000+20,000+9,000+200+50+1
You might be interested in
3x - 4 = -31 What is x?
SSSSS [86.1K]
3x-4=-31
+4 +4
3x=27
X=9

Hope this helps
5 0
3 years ago
Read 2 more answers
Write the value of the digit of 281'480'100
topjm [15]
Ummmm....
one hundred thousands place
i don't get what u mean by it
6 0
3 years ago
The height to the base of an isosceles triangle is 12.4m, and its base is 40.6m. What are the measurement of the angles of the t
Vsevolod [243]

Answer:

  • angles: 31.42°, 31.42°, 117.16°
  • legs: 23.79 m

Step-by-step explanation:

The base angles can be found from the definition of the tangent function:

  tan(base angle) = height/(half-base length)

  base angle = arctan(12.4/20.3) ≈ 31.418°

Then the apex angle is double the complement of this:

  apex angle = 2(90° -31.418°) ≈ 117.164°

The base angles are 31.42°, and the apex angle is 117.16°.

__

The leg lengths can be computed from the Pythagorean theorem applied to the altitude and the half-base length.

  leg length = √(12.4² +20.3²) = √565.85 ≈ 23.789 . . . . meters

The length of the legs is about 23.79 m.

5 0
3 years ago
Read 2 more answers
How many significant digits are in thus number 74.30
goblinko [34]

Answer:

3

Step-by-step explanation:

all numbers except from zero

that would mean 7 4 and 3

so there would be 3 significant figures

I hope it goes well

7 0
3 years ago
This problem uses the teengamb data set in the faraway package. Fit a model with gamble as the response and the other variables
hichkok12 [17]

Answer:

A. 95% confidence interval of gamble amount is (18.78277, 37.70227)

B. The 95% confidence interval of gamble amount is (42.23237, 100.3835)

C. 95% confidence interval of sqrt(gamble) is (3.180676, 4.918371)

D. The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

Step-by-step explanation:

to)

We will see a code with which it can be predicted that an average man with income and verbal score maintains an appropriate 95% CI.

attach (teengamb)

model = lm (bet ~ sex + status + income + verbal)

newdata = data.frame (sex = 0, state = mean (state), income = mean (income), verbal = mean (verbal))

predict (model, new data, interval = "predict")

lwr upr setting

28.24252 -18.51536 75.00039

we can deduce that an average man, with income and verbal score can play 28.24252 times

using the following formula you can obtain the confidence interval for the bet amount of 95%

predict (model, new data, range = "confidence")

lwr upr setting

28.24252 18.78277 37.70227

as a result, the confidence interval of 95% of the bet amount is (18.78277, 37.70227)

b)

Run the following command to predict a man with maximum values ​​for status, income, and verbal score.

newdata1 = data.frame (sex = 0, state = max (state), income = max (income), verbal = max (verbal))

predict (model, new data1, interval = "confidence")

lwr upr setting

71.30794 42.23237 100.3835

we can deduce that a man with the maximum state, income and verbal punctuation is going to bet 71.30794

The 95% confidence interval of the bet amount is (42.23237, 100.3835)

it is observed that the confidence interval is wider for a man in maximum state than for an average man, it is an expected data because the bet value will be higher than the person with maximum state that the average what you carried s that simultaneously The, the standard error and the width of the confidence interval is wider for maximum data values.

(C)

Run the following code for the new model and predict the answer.

model1 = lm (sqrt (bet) ~ sex + status + income + verbal)

we replace:

predict (model1, new data, range = "confidence")

lwr upr setting

4,049523 3,180676 4.918371

The predicted sqrt (bet) is 4.049523. which is equal to the bet amount is 16.39864.

The 95% confidence interval of sqrt (wager) is (3.180676, 4.918371)

(d)

We will see the code to predict women with status = 20, income = 1, verbal = 10.

newdata2 = data.frame (sex = 1, state = 20, income = 1, verbal = 10)

predict (model1, new data2, interval = "confidence")

lwr upr setting

-2.08648 -4.445937 0.272978

The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

4 0
3 years ago
Other questions:
  • This partial circle has a radius of 11 inches.
    12·2 answers
  • Estimate the sum 258+565
    14·1 answer
  • A different car can travel 30.5 miles for every gallon of gas used.
    11·2 answers
  • What is 35/75 reduced to
    14·2 answers
  • What is the graph of y = 0.4x
    10·2 answers
  • The school hiking club has completed 4 out of 5 hikes so far this year. They have hiked 4.6 miles, 3.7 miles, 5.1 miles, and 2.9
    11·2 answers
  • 1) In the year 2010, Shaniya invested $1 in the stock market. In the year 2022, her $1 was worth $2. In the year 2034, it was wo
    10·1 answer
  • What are the first five terms of the explicit function
    10·1 answer
  • A cone-shaped paper cup can hold 35 cubic inches of food. If the radius of the cone is 2.4 inches, what is the height of the con
    14·1 answer
  • What store is offering the best sale <br> 8 for $6<br> 10 for $10<br> 2 for $3<br> 0.80 cents each
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!