Given a quadratic equation in standard form
The discriminant D
tells the types of roots the equation has.
In this case, we have
Then, the discriminant of this quadratic equation will be
Finally, the value of discriminat is 49 and as he discriminant is greater than zero then this quadratic equation has 2 different real solutions.
Looks more like Trig than Algebra II
They want us to apply the sum angle formula to
5π/6 is 150°; I find it easier to think in degrees.
When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.
The sine sum angle formula is
We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2
Third choice