Answer:
Step-by-step explanation:
13-2x 5
13-5= 8
2x 8
G2=g1*2
g3=g1*2²
196=x*4
/4 /4
49
No the following coordinates do not show a function because of the y-values. In the pairs that you have, (3,5) and (0,5) have the y-values of "5" that are repeating.
Hope this helps. I learned that in math.
Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
Answer:
since the ratio of y to x (also written y:x) never changes. The number 6 in the equation yx=6 y x = 6 is called the constant of variation. The equation yx=6 y x = 6 can also be written in the equivalent form, y=6x y = 6 x .
Step-by-step explanation:
The answer is True