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mars1129 [50]
3 years ago
14

Can someone pls help me

Mathematics
1 answer:
Yuri [45]2 years ago
6 0

Answer:

I'm not sure, but I'll try

Step-by-step explanation:

(Side)^2 = (Hypotenuse)^2 - (Side)^2

(Side)^2 = (9)^2 - ( √ 65 )^2

(Side)^2 = (81) - (65)

(Side)^2 = 16

Take root of answer

Side = √16

Side = 4

Answer = 4

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What is the coefficient of x in the equation?<br> y=x+4
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Answer:

1

Step-by-step explanation:

When a variable does not have a visible coeffecient then the coefficient is 1. (Double check to make sure I'm correct)

4 0
3 years ago
3. You need to hire a taxi. Taxi A charges $9.25 plus $1.50 per mile. Taxi B charges $10.50 plus $1.25 per mile. Find the number
lapo4ka [179]

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five miles

Step-by-step explanation:

taxi A: for one mile: 10.75

taxi B: for one mile: 11.75

two miles: A: 12.25 B: 13

three miles: A: 13.75 B: 14.25

four miles: A: 15.25 B: 15.5

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5 0
2 years ago
Math help please please I’m not gonna believe those links don’t try
Rainbow [258]

Answer:

C

Step-by-step explanation:

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3 0
3 years ago
If the replacement set is the set of integers, find the solution set for the inequality:
kakasveta [241]
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8 0
3 years ago
Read 2 more answers
How do you do these 2 questions?
zavuch27 [327]

Answer:

0 ≤ an ≤ bn

The series ∑₁°° bn converges

The series ∑₁°° an converges by comparison to ∑₁°° bn.

0 ≤ an ≤ bn

The series ∑₁°° bn diverges

The comparison test is inconclusive for our choice of bn.

Step-by-step explanation:

an = 1 / (n² + n + 3) and bn = 1 / n²

The numerators are the same, and the denominator of an is greater than the denominator of bn.  So 0 ≤ an ≤ bn.

bn is a p series with p > 1, so it converges.

Since the larger function converges, the smaller function also converges.

an = (3n − 1) / (6n² + 2n + 1) and bn = 1 / (2n)

If we rewrite bn as bn = (3n − 1) / (6n² − 2n), we can tell that when the numerators are equal, the denominator of an is greater than the denominator of bn.  So 0 ≤ an ≤ bn.

bn is a p series with p = 1, so it diverges.

The larger function diverges.  We cannot conclude whether the smaller function converges or diverges.

5 0
3 years ago
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