Answer:
Step-by-step explanation:
domain is (-3,x) x- inter
range is (x,2) y-inter
Answer:
The 1st table represents a function
Step-by-step explanation:
Answer:
4 ways
Step-by-step explanation:
1 gummy 4 chocolates
2 gummy 3 chocolates
3 gummy 2 chocolates
4 gummy 1 chocolates
This is what i think the answer is hope it helps
we have

<u>Statements</u>
<u>case A)</u> The graph is a straight line.
The statement is True
Because, this is a linear equation (see the attached figure)
<u>case B)</u> The line passes through the origin.
The statement is False
Because the point
is not a solution of the equation
Verify
Substitute the value of x and y in the equation

------> is not true
the point
is not a solution
therefore
The line does not pass through the origin
<u>case C)</u> The line passes through the point 
The statement is True
Because the point
is a solution of the equation
Verify
Substitute the value of x and y in the equation

------> is true
the point
is a solution
therefore
The line passes through the point 
<u>case D) </u>The slope of the line is 
The statement is False
Because, the slope of the line is 
<u>case E)</u> The y-intercept of the line is 
The statement is False
we know that
The y-intercept is the value of y when the value of x is equal to zero
so
For 
find the value of y

the y-intercept is equal to 
Answer:
The space inside the box = 2197 in³ - 1436.76 in³ is 760.245 in³.
Step-by-step explanation:
Here we have the volume of the cube box given by the following relation;
Volume of cube = Length. L × Breadth, B × Height, h
However, in a cube Length. L = Breadth, B = Height, h
Therefore, volume of cube = L×L×L = 13³ = 2197 in³
Volume of the basketball is given by the volume of a sphere as follows;
Volume = 
Where:
r = Radius = Diameter/2 = 14/2 = 7in
∴ Volume of the basketball = 
Therefore, the space inside the box that is not taken up by the basketball is found by subtracting the volume of the basketball from the volume of the cube box, thus;
The space inside the box = 2197 in³ - 1436.76 in³ = 760.245 in³.