If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
Jason = J Bill = B Sharon = S
J = 5+B
B= 2×S
J= 5+ (2×S)
The formula for the volume of a cone is V=(1/3)πr^2h.
To find r (radius) divide the diameter by 2, giving you 2.5 cm.
Plug in the numbers now !
V=(1/3)(3.14)(2.5^2)(9)
V=(1/3)(3.14)(6.25)(9)
V=(1/3)(176.625)
V=58.875
Therefore, the volume of the cone is about 59cm^3 :)
Answer:
28
Step-by-step explanation:
16−(−12)
=16−(−12)
=16+12
=28
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28 is your answer
(Hope it helps)
