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Basile [38]
3 years ago
13

Determine a series of transformations that would map figure L onto figure M

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0
A 270 degree Rotation
faust18 [17]3 years ago
8 0

Answer:

Translation followed by a Rotation.

Step-by-step explanation:

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{4.OA.A.3} There are 1,492 chairs in the auditorium. Ms. Jones wants to put them into 10 rows. If she splits the chairs evenly i
chubhunter [2.5K]

Answer:

2 chairs will be left over.

Step-by-step explanation:

Given that

There are a total of 1492 chairs.

which are to divided in 10 rows evenly.

To find:

Number of chairs left ?

Solution:

Let the number of chairs in each row = x

There are 10 rows so number of chairs in rows = 10x

Let the number of chairs left = y

Total number of chairs =10x + y  = 1492

The above equation is like:

Divisor \times Quotient + Remainder = Dividend

So, we have to find the remainder in this question where we are given Divisor and Dividend.

10 \times 149 + 2 = 1492

So, dividing 1492 with 10, we get remainder as 2.

Hence, 2 chairs will be left.

7 0
3 years ago
I don't understand this question can someone help me with this please, please explain!! and thank you for the help!! If u dont k
marta [7]

Answer:

The answer to the first question on the first page is 3

The answer to the first question on the second page is 3/4

The answer to the second question on the second page is 1/4

Step-by-step explanation:

I dont know the second question on page 1

4 0
3 years ago
Read 2 more answers
find the equation of the tangent to the curve y=x^2-2x-3 at the points where the line y=5 cuts the parabol​
olchik [2.2K]

ugh i hate tangents. never understood it

5 0
3 years ago
7 measured data points have a sample mean of 1403 and a standard deviation of 27. Determine the best estimate of the mean value
mina [271]

Answer:

Step-by-step explanation:

Hello!

You have sample of n=7 with mean X[bar]= 1403 and standard deviation S=27 and are required to estimate the mean with a 95%CI.

Asuming this sample comes from a normal population I'll use a stuent t to estimate the interval (a sample of 7 units is too small for the standard normal to be accurate for the estimation):

[X[bar]±t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{n} }]

t_{n-1;1-\alpha /2} = t_{6;0.975}= 2.365

[1403±2.365*\frac{27}{\sqrt{7} }]

[1378.87;1427.13]

The margin of error is the semiamplitude of the interval and you can calculate it as:

d= \frac{Upbond-Lowbond}{2}= \frac{1427.13-1378.87}{2} = 24.13

With a confidence level of 95% you'd expect that the real value of the mean is contained by the interval [1378.87;1427.13], the best estimate of the mean value is expected to be ± 24.13 of 1403.

I hope it helps!

4 0
3 years ago
What is the length of AB
Anettt [7]

Answer:

\boxed{\boxed{\overline{AB}=16}}

Step-by-step explanation:

In the triangle ABC, m∠ABC=90°. Hence, it is right angle triangle.

\tan \theta=\dfrac{p}{b}=\dfrac{AB}{64}  --------1

In the triangle ABD, m∠ABD=90°. Hence, it is right angle triangle.

\cot (90-\theta)=\dfrac{b}{p}=\dfrac{4}{AB}

As \cot (90-\theta)=\tan \theta, so

\tan \theta=\dfrac{b}{p}=\dfrac{4}{AB}  ---------2

From equation 1 and 2,

\Rightarrow \dfrac{AB}{64}=\dfrac{4}{AB}

\Rightarrow AB^2=64\times 4

\Rightarrow AB^2=256

\Rightarrow AB=\sqrt{256}

\Rightarrow AB=16


5 0
3 years ago
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