Answer: If it is probability, there is a 40% chance that a school will receive a defective calculator if the selections are random.
If the calculators are tested and sorted, there can be 3 selections of 4 calculators sent to schools once the 8 defective ones are removed.
Step-by-step explanation: The question is unclear. Is it about subtracting the bad ones and dividing the good ones? Or is it about Taking chances with the selection of calculators to be sent?
If they subtract: 20-8= 12 left 12÷4= 3 sets of good ones.
If they take chances 8/20 = .4 so there is a 40% chance that a bad calculator will be included in the selection.
Answer:
B. TRUE.
(3, 2) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
Step-by-step explanation:
Option B is TRUE because intersection point should satisfy both the equation
and in option be it comes true.
i.e x = 3 and y = 2 we have
3 + 2 = 5 and 3 - 2 = 1
5 = 5 and 1 = 1
Hence TRUE
A.
(3, 2) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 3 and y = 2 we have
3×3 + 2×2 = 5 and 3×3 - 2×2 = 1
13 ≠ 5 and 5 ≠ 1
Hence FALSE
C.
(5, 1) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 5 and y = 1 we have
3×5 + 2×3 = 5 and 3×5 - 2×3 = 1
21 ≠ 5 and 9 ≠ 1
Hence FALSE
D.
(5, 1) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
i.e x = 5 and y = 1 we have
5 + 1 = 5 and 5 - 1 = 1
6 ≠ 5 and 4 ≠ 1
Hence FALSE
Answer:
Ge I Joe 02 04 Soccer balls height
Answer:
Summed?
Step-by-step explanation:
it's the only word i could think of that's math related.
Answer:
A # is odd
Step-by-step explanation:
Hypothesis-----> conclusion
