Flipping two coins gives four possibilities: HH, HT, TH, TT
So P(TT)=1/4
So we'd expect a quarter of the trials to be two tails.
trials expected to be two tails.
So P(TT)=1/4
So we'd expect a quarter of the trials to be two tails.
Which equation, when solved, results in a different value of x than the other three? O -7-9-20 0 + 5 3 7 X=-20 4 O 3 4. - (b)*--
1 answer:
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