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andre [41]
3 years ago
6

Given the equation (x+a)^2(x-2)=x^3+bx^2+12x-72 find a and b

Mathematics
1 answer:
GaryK [48]3 years ago
7 0
Isolate the variable by dividing each side by factors that don't contain the variable.

a=-  \frac{ x^{2}-  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,-  \frac{ x^{2}+  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variabel.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible 
 

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Cot x = cos x / sin x
cot π/4 = cot 45° = cos 45° / sin 45°
We know that sin 45° and sin 45° have the same value:
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cos 45° / sin 45° = √2/2 : √2/2 = 1
Answer:
cot π/4 = 1
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Pani-rosa [81]

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8 0
3 years ago
Please help
Mnenie [13.5K]

<u>Given</u>:

Given that the radius of the sphere is 9 cm

We need to determine the volume of the sphere.

<u>Volume of the sphere:</u>

Let us determine the volume of the sphere.

The volume of the sphere can be determined using the formula,

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where r is the radius of the sphere.

Substituting r = 9 in the above formula, we get;

V=\frac{4}{3} \pi (9)^3

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V=972 \pi

Thus, the volume of the sphere is 972π cm³

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