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olga55 [171]
3 years ago
13

x^{3} y^{2} z)(2xy^{5} z^{5}" alt="(3x^{3} y^{2} z)(2xy^{5} z^{5}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
castortr0y [4]3 years ago
8 0
<h3 /><h3>( {3x}^{2}  {y}^{2} z) \: ( {2xy}^{5}  {z}^{5} ) \\  = 6  {x}^{2}  {y}^{2}  {xy}^{5}  {z}^{6}</h3><h3>[ Multiply all digits and variables according to there same value ]</h3>

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>

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Find the mean absolute deviation (MAD) of the data set of 0.4, 0.2, 0.4, 0.6
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Assuming data is from population, 0.1

Step-by-step explanation:

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I'm confused how you split the fraction
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1/3 + 1/3 + 1/3 + 1/3 + 1/3 + 1/3 = 6/3 
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The bees buzzed by the beatiuful blue bag, what is this?
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Alliteration

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in a circular garden the distance from the center of the circle to the edge is 15ft . If a gardner wants to plant roses in a 60
olya-2409 [2.1K]

Answer:

Approximately 117.81 ft²

Step-by-step explanation:

Find the area of the whole circle

A=πr²

A=π(15)²

A=706.86 ft²

Now you need to find the area of the garden covered in roses, so take the total degrees in a circle (360) and divide it by the degrees of the roses (60).

360/60=6

Take the area of the whole circle (706.86 ft²) and divide it by the number you just got (6). The number you get will be the area of the rose section.

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6 0
3 years ago
The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr
Kobotan [32]

Answer:

%  change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

T = 2.5 x + 0.5 x^{2}

We will approximate this distance  using the relation

f (x + dx) = f (x)+ f' (x)dx

dx = 26 - 25 = 1

T' =  2.5 + x

Therefore

f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× 25^{2} + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × 25^{2}

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

%  change in stopping distance = \frac{27.5}{375} × 100

%  change in stopping distance = 7.34 %

6 0
3 years ago
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