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Blizzard [7]
2 years ago
12

Write an equation of the circle with center (-6, 2) and diameter 10.

Mathematics
1 answer:
marshall27 [118]2 years ago
6 0

Solution:

We know that the formula to write the equation of a circle is (x – h)² + (y – k)² = r², where h is the x coordinate, k is the y-coordinate, r is the radius of circle, and the center of circle is (-6,2).

<u>Finding the radius of the circle.</u>

  • Diameter: 10 units
  • Radius: 10/2 units = 5 units

<u>Creating the equation:</u>

  • (x – h)² + (y – k)² = r²
  • => (x + 6)² + (y – 2)² = 5²

The equation is (x + 6)² + (y – 2)² = 5².

Learn more: brainly.com/question/26573763

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Find the gain or loss per cent, if <br>C.P. = 200 and S.P. = 224​
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3 years ago
5k^3-8-4k^2+5k^2-2+3k^3
lara31 [8.8K]
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>

-----------------------------------------------------------------------

5k^3-8-4k^2+5k^2-2+3k^3

Group like terms:

5k^3+3k^3-4k^2+5k^2-8-2

Add similar elements:

5k^3+3k^3+k^2-8-2

Add similar elements:

8k^3+k^2-8-2

Subtract the numbers:

8k^3+k^2-10

Your Answer Is 8k^3+k^2-10

Plz mark me as brainliest :)

7 0
3 years ago
Help me please !!!
Nat2105 [25]

Answer:

For 3x^2+4x+4=0

Discriminant= = -32

The solutions are

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= -44

The solutions

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= -36

The solutions

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a= (1-√-1)/3

Step-by-step explanation:

Formula for the discriminant = b²-4ac

let the discriminant be = x for the equations

The solution of the equations

= (-b+√x)/2a and = (-b-√x)/2a

For 3x^2+4x+4=0

Discriminant= 4²-4(3)(4)

Discriminant= 16-48

Discriminant= = -32

The solutions

(-b+√x)/2a =( -4+√-32)/6

(-b+√x)/2a= (-4 +4√-2)/6

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a =( -4-√-32)/6

(-b-√x)/2a= (-4 -4√-2)/6

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= 2²-4(3)(4)

Discriminant= 4-48

Discriminant= -44

The solutions

(-b+√x)/2a =( -2+√-44)/6

(-b+√x)/2a= (-2 +2√-11)/6

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a =( -2-√-44)/6

(-b-√x)/2a= (-2 -2√-11)/6

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= (-6)²-4(9)(2)

Discriminant= 36 -72

Discriminant= -36

The solutions

(-b+√x)/2a =( 6+√-36)/18

(-b+√x)/2a= (6 +6√-1)/18

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a =( 6-√-36)/18

(-b-√x)/2a= (6 -6√-1)/18

(-b-√x)/2a= (1-√-1)/3

6 0
3 years ago
Please Answer This, the question is on the picture. it needs to be a fraction
marshall27 [118]

Answer:

x = 33

Step-by-step explanation:

sin 29° = 16/x

x = 33

3 0
3 years ago
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