Answer:
5^(3)i^(9)= five cubes times i to the power of 9=125i
Step-by-step explanation:
Raise 5 to the power of 3
rewrite i9 as (i^4)2^i
so, you get 125((i^4)^2i)
i^4=1
125(1^2i)
125i
Answer:
66
Step-by-step explanation:
If there are <em>n</em> students, then the number of pairs is
.
With 12 students,
pairs can be formed.
The reason the formula works is this: Each of the 12 students can be paired with 11 other students (no student is paired with him/her self). But counting 12 x 11 = 132 counts each pair <u>twice</u>. Example: student A can be paired with student B,..., student B can be paired with student A. The pair was counted two times.
See the attached image that shows pairings of 5 students. There are
5(5 - 1)/2 = 5(4)/2 = 10 pairs.
Let’s find 1% of the markup first.
20 x 0.01 = $0.20
$0.20 x 8 = $1.60 markup.
$20 + $1.60 = $21.60 total.
Adrianna made $21.60 total, including markup.
Hope that helped! :)
Answer:
∠HDC ≅ ∠HDE, AB ≅ BC, HC ≅ HE
Step-by-step explanation:
yup