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Alex777 [14]
2 years ago
7

Jessica is stacking items on a shelf she has large books that weigh 5 pounds each and medium books that weigh 3 pounds each. The

shelf should hold at most 50 pounds.
Let x represent the number of large books.
Let y represent the number of medium books.

Which inequality represents the situation?

a.) 5x + 3y < 50 b.) 5x +3y ≤ 50 c.) 5x + 3y ≥ 50 d.) 5x + 3y > 50
Mathematics
1 answer:
umka2103 [35]2 years ago
8 0

Answer:

b) 5x +3y ≤ 50

Step-by-step explanation:

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51

Step-by-step explanation:

1 mL = 0.034 fluid ounces

(500 + 1000) x 0.034

= 51 fluid ounces

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Find the transformations from y=x^2 for the following equation: f(x)=(x+4)^2 -9
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Y=x^2 moves right 4, down 9.
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Simplify.<br> 5V18-2V50<br> V50
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Answer:

-500

Step-by-step explanation:

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2 years ago
The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 25
Assoli18 [71]

Answer:

(a) The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b) The projectile reaches its maximum height  after 2.60 s of projection.

(c)The maximum height that is attained by the projectile is 37.18 m.

(d)Therefore the projectile hits the ground after 5.36 seconds of projection.

(e)The velocity of the projectile when it hits the ground is 27.03 m/s

Step-by-step explanation:

Given that, a projectile shot vertically upward from a point 4 m above the ground with a initial velocity of 25.5 m/s.

The height of the projectile after t seconds is

h=4+25.5t-4.9t^2

where h is in meter.

(a)

We use the formula

v=u+at

V= final velocity

u = initial velocity = 25.5 m/s

a = acceleration=   acceleration due to gravity= 9.8 m/s²

Since the object moves upward direction and acceleration due to gravity is downward direction. So here a= -9.8 m/s.

v(2)= 25.5+(-9.8)×2

     =25.5-19.6

     =5.9 m/s

And when t= 4

v(4)= 25.5+(-9.8)×4

    =25.5-39.2

    = -13.7 m/s

The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b)

At its maximum height,the velocity of the projectile is zero. i.e v=0

∴0=25.5+(-9.8)t

⇒9.8t=25.5

\Rightarrow t=\frac{25.5}{9.8}

⇒t = 2.60 s

The projectile reaches its maximum height  2.60 s after projection.

(c)

To find the maximum height, we are putting t= 2.60 in this equation h=4+25.5t-4.9t^2.

\therefore h= 4+(25.5\times 2.60)-(4.9\times 2.60^2)

     =37.18 m

The maximum height that is attained by the projectile is 37.18 m.

(d)

When the projectile hits the ground the height will be zero i.e h=0

From the equation of height we get

\therefore h=0=4+25.5t-4.9t^2

\Rightarrow 4+25.5t-4.9t^2=0

\Rightarrow t=\frac{-25.5\pm\sqrt{25.5^2-4(-4.9).4}}{2(-4.9)}

⇒t= -0.15 ,5.36

Therefore it hits the ground after 5.36 seconds of projection.

(e)

To find the velocity we use the formula v=u+at

Here v = final velocity=?

u=25.5 m/s,

t = 5.36 s

a= -9.8m/s²

v=25.5+(-9.8)5.36

 = -27.03 m/s

Negative sign denoted that the motion of the projectile is downward direction.

The velocity of the projectile when it hits the ground is 27.03 m/s.

6 0
3 years ago
In New Salem North Dakota there is a 38-ft-tall statue of a cow named Salem Sue. Suppose the statue's shadow was 57 feet long an
guajiro [1.7K]

Answer:

5.25 feets

Step-by-step explanation:

Given that:

Height of Salem Sue = 38 feets

Height of Salem Sue's shadow = 57 feets long

Height of child standing next to the statue = 3.5 foot tall

Length of the child's shadow =?

Let lenght of child's shadow = s

IF;

38 Feets tall = 57 feets lenght

3.5 feets tall = s feets long

Cross multiply :

38 * s = 57 * 3.5

38s = 199.5

38s / 38 = 199.5 /38

s = 5.25

Hence, length of the child's shadow will be 5.25 feets long

3 0
3 years ago
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