The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
Read more about distance at
brainly.com/question/1872885
#SPJ1
It is substitution. Because you are substituting 3=y into x+5=3
Answer:
15+n
Step-by-step explanation:
Let the number be 'n'
Fifteen=15
increased by= +
a number= n
Hope this helps ;) ❤❤❤
A graph shows the appropriate choice to be
A. 277.8 °F
_____
Of course, you get the same result by evaluating
76 + 301*e^(-0.40)