let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
A) (4, -2)
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Step 1: find BC
Given Triangles ABC and ADE are similar,
=
BC =
x DE
=
x 9
= 6 cm
Step 2: use Pythagorean theorem to find AC and / or AE
Consider triangle ABC,
by Pythagorean theorem,
AB² + BC² = AC²
AC² = 6² + 8² = 100
AC = √100 = 10 (answer... we can see that C is the only one with AC=10.
Step 3: Verify.. even though we know that it is C because AC = 10, you can verify that the ansewer is correct by finding CE and confirming that CE=5
By using similar triangles ABC and ADE,
AC/AE = AB / AD
AE = AD/AB x AC = 12/8 x 10 = 15
CE = AE - AC = 15 - 10 = 5 (answer confirmed)
Answer:
22
Step-by-step explanation:
Generate the terms of sequence T using the nth term formula n² - 3
a₁ = 1² - 3 = 1 - 3 = - 2
a₂ = 2² - 3 = 4 - 3 = 1
a₃ = 3² - 3 = 9 - 3 = 6
a₄ = 4² - 3 = 16 - 3 = 13
a₅ = 5² - 3 = 25 - 3 = 22
22 is common to sequence S and T
Answer:
it y = 2x + b
Step-by-step explanation:
YOU NEED TO PUT THE M FIRST NOT THE X