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Gnom [1K]
2 years ago
15

Can anyone please help me I know it’s right I don’t know why it’s staying it’s wrong

Mathematics
1 answer:
svlad2 [7]2 years ago
4 0

Answer:well If it says its wrong then it may be wrong some times is you think its right its not always right

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PLS HELP ILL GIVE U BRAINLIEST
vekshin1
The answer to this question would be the second option “10m + 5 > 100” because 10 a month so (10m) then he purchases 5 extra per month so + 5 then his total collection is MORE so greater than 100 games so > 100 so the outcome is “10m + 5 > 100”
5 0
3 years ago
Read 2 more answers
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
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Answer:

well my brothers parakeet died 2 days ago sooooooooooooo......

Step-by-step explanation:

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Answer:

Increasing

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Step-by-step explanation:

8 0
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Answer:

Step-by-step explanation:

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