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Slav-nsk [51]
3 years ago
10

Help ill give brainly

Mathematics
2 answers:
earnstyle [38]3 years ago
5 0

Answer:

The answer would be 26%

Step-by-step explanation:

kicyunya [14]3 years ago
4 0

Answer:27  

i think that 27 is the answer

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Identify the values of variables x, y, and z based on the image given of the angles formed by a transversal and parallel lines
Paul [167]

Answer:

x=62\\y=94\\z=94

Step-by-step explanation:

Let's start by identifying relevant angle theorems for two parallel lines cut by a transversal.

Alternate Interior Angles Theorem

Two angles that are on different sides of the transversal and inside of the two parallel lines are congruent (=).

Alternate Exterior Angles Theorem

Two angles that are on different sides of the transversal and outside of the two parallel lines are congruent (=).

Same-side Interior Angles Theorem

Two angles that are on the same side of the transversal and inside of the two parallel lines are supplementary (= 180).

Same-side Exterior Angles Theorem

Two angles that are on the same side of the transversal and outside of the two parallel lines are supplementary (=180).

Corresponding Angles Theorem

Two angles on a figure that correspond are congruent (=).

_

Now, let's look at the figure and apply these theorems.

z and 86 are same-side exterior angles, meaning they're supplementary:

z+86=180

Subtract 86 from both sides of the equation:

z=94

Now that we know our z value, let's recognize that z (94)corresponds to x+32, meaning they're congruent:

x+32=94

Subtract 32 from both sides of the equation:

x=62

Let's find the value of the angle:

(62)+32

Add:

94

Since the corresponding angles are of the same value, they're congruent, proving our x & z values correct.

_

Since y and the angle represented by the expression x+32 (94°) are alternate-interior angles, they are congruent:

y=94

5 0
4 years ago
What is the simplified form of 4 log3y - 6 log3x + 7 log3z?
GaryK [48]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

[ b ] is the Correct one

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:4  \: log_{3}(y)  - 6 \:  log_{3}(x)  + 7 \:  log_{3}(z)

\qquad❖ \:  \sf \: \: log_{3}(y {}^{4} )  -  \:  log_{3}(x {}^{6} )  +\:  log_{3}(z {}^{7} )

\qquad❖ \:  \sf \: \: log_{3}(y {}^{4} )   +  \:  log_{3}(z{}^{7} )   - \:  log_{3}(x {}^{6} )

(\sf a\: log (b) = log {b}^{a})

\qquad❖ \:  \sf \: log_{3}( {y}^{4} {z}^{7}  )  -  log_{3}( {x}^{6} {}^{}  )

(\sf{log (a) + log (b) = log (ab)})

\qquad❖ \:  \sf \:    log_{3} \bigg( \dfrac{y {}^{4} {z}^{7}  }{ {x}^{6} } \bigg )

(\sf{log (a) - log (b) = log (a/b)})

\qquad \large \sf {Conclusion}  :

[ b ] is the Correct choice

4 0
2 years ago
Determine whether each equation represent a proportional relationship a. y=2.5x b. y=x-4
Nastasia [14]
The 2.5x would be a proportional relationship
5 0
3 years ago
What number must you add to complete the square?
Travka [436]
B=9 (x+3)^2= x^2+6x+9
7 0
3 years ago
A ship's mast is sighted just over the horizon at 4 nautical miles. How far is this in kilometers? There are 1.609 kilometers in
PtichkaEL [24]

Answer:

This is <u>7.408 kilometres</u> far.

Step-by-step explanation:

Given:

A ship's mast is sighted just over the horizon at 4 nautical miles.

Now, to find the distance in kilometers.

As, given ship's mast is sighted just over the horizon at 4 nautical miles.

So, by using conversion factor we get the nautical mile into kilometers:

<em>1 nautical mile = 1.852 kilometer.</em>

<em>Thus, 4 nautical miles</em>

= 4\times 1.852

=  7.408\ kilometers.

Therefore, this is 7.408 kilometres far.

5 0
3 years ago
Read 2 more answers
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