Answer:
- Please see the attached picture for full solution!:)
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The answer is 7. You can look at it like this. The two triangles are similar and the larger one's sides are twice the size of the smaller one's. So then we know GF is twice the size of JK.
2(2y+5)=5y+3
4y+10=5y+3
y=7
Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be
4x + 2y = 20
There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.
When x=0,
4(0) + 2y = 20
y = 10
When x=1,
4(1) + 2y = 20
y = 8
When x=2,
4(2) + 2y = 20
y = 6
When x=3,
4(3) + 2y= 20
y = 4
When x = 4,
4(4) + 2y = 20
y = 2
When x = 5,
4(5) + 2y = 20
y = 0
When x = 6,
4(6) + 2y = 20
y = -2
A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:
Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0
Step-by-step explanation:
Find the slope of JK by the formula :y2-y1/(x2-x1) whose value is 4/5
similarly, calculate the slope of GH it's value is also 4/5
Find slope of GK now by same formula y2-y1/( x2-x1 ).the value will be -5/3
Similarly calculate slope of HJ and you will get its value to be -5/3
since parallel lines have equal slopes JK and GH are parallel and GK and HJ are parallel. Since opposite sides are parallel GHJk is parallelogram
Step-by-step explanation:
Area of shaded =Area of Outer rectangle - Area of Inner rectangle.
Area of inner rectangle = L× B.
L=18
B=11
Area of inner rectangle = 18×11
=198m^2
To find the full breadth of the outer rectangle
=2 in +11 + 2 in
=15
To find the full length of the outer rectangle
=2 in + 18 + 2 in
=22
Area= 22 × 15
Area = 330m^2
Area of shaded portion = 330 - 198
=132m^2
