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PSYCHO15rus [73]

3 years ago

12

a story has a contest to guess the mass of 10000 peanuts. If a peanut has a mass of about 0.45 then what would be a reasonable g

uess for the mass of 10000

2 answers:

mamaluj [8]3 years ago

7 0

1000000 i think...................................................

Alex_Xolod [135]3 years ago

7 0

Around 4,500 because .45 times 10000 = 4,500

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Which equation is y= 2x ^2 - 8x +9 rewritten in vertex form.

tankabanditka [31]

<span>y= 2x ^2 - 8x +9

</span>y = a(x - h)2 + k, where (h, k) is the vertex<span> of the parabola
</span>so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------<span>vertex form</span>

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3 years ago

16) The manager of a bulk foods establishment sells a trail mix for $8 per

zaharov [31]

Answer:

The amount of peanuts to use is 5 pounds and that of cashews is 30 pounds.

Step-by-step explanation:

Let the amount of peanut to use to be x

Let the amount of cashews to use to be 35-x

Form equations to compare amounts for individual foods and the mixture

$8x+15(35-x)=35(14)\\\\8x+525-15x=490\\\\7x=35\\\\x=5\\\\$

So the pounds to be used for peanuts is 5 pounds

The pounds to be used for cashews will be 35-x= 35-5=30 pounds

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Mixtures : brainly.com/question/11497620

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4 years ago

Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim

sergejj [24]

Answer:

a) Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

b) $t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958$

c) $p_v =P(t_{34}>2.958)=0.0028$

d) If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.

Step-by-step explanation:

Data given and notation

The sample mean is given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And the sample deviation is:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=17$ represent the sample mean

$s=4$ represent the sample standard deviation

$n=35$ sample size

$\mu_o =15$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part b Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958$

Part c P-value

The degrees of freedom are given by:

$df = n-1= 35-1=34$

Since is a right tailed test the p value would be:

$p_v =P(t_{34}>2.958)=0.0028$

Part d Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.

7 0

3 years ago

What is the quotient? URGENT!!

jeyben [28]

Answer:

The answer is A.

Step-by-step explanation:

You have to multiply by converting the second fraction into upside down :

$\frac{4x + 1}{6x} \div \frac{x}{3x - 1}$

$= \frac{4x + 1}{6x} \times \frac{3x - 1}{x}$

$= \frac{(4x + 1)(3x - 1)}{x(6x)}$

$= \frac{12 {x}^{2} - 4x + 3x - 1}{6 {x}^{2} }$

$= \frac{12 {x}^{2} - x - 1 }{6 {x}^{2} }$

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3 years ago

A club is selling hats and jackets as a fundraiser. Their budget is $1500, and they want toorder at least 250 items. Each hat co

Tom [10]

Let H be the number hats and J the number of jackets. Then, we can write,

$5H+8J\le1500$

Now, since they want 250 items at least, we can write

$H+J\le250$

Hence, the system of inequalities is

$\begin{gathered} 5H+8J\le1500 \\ H+J\le250 \end{gathered}$

6 0

1 year ago