Ask question

Ask question

All categories

3 years ago

12

Will give brainliest PLs help Here is the argument you are presenting: There is a need for students to understand and be able to

construct geometric figures using a compass and straightedge. Write three reasons that support this argument

1 answer:

Natasha2012 [34]3 years ago

4 0

1. It is easier to apply it to real-world situations once you have learned to construct geometric figures using compasses and straightedges.

2. Constructing geometric figures yourself also helps you understand the material and learn easily.

3. There is more accuracy and it is easier to prove your accuracy in your own constructions.

I hope this helps :)

You might be interested in

What is the area of the second triangle

blagie [28]

Answer:

To find the area of a triangle, multiply the base by the height, and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into 2 triangles. For example, in the diagram to the left, the area of the parallelogram.

8 0

4 years ago

What is the value of y in the equation 2 + y = -3 ?

Stels [109]

Answer:

y=- -5 (negative 5)

Step-by-step explanation:

5 0

3 years ago

In evaluating a double integral over a region D, a sum of iterated integrals was obtained as follows:

BabaBlast [244]

Answer

$a=0$ , $b=2$

$g_1(x)=\frac{5x}{2}$ , $g_2(x)=7-x$

Step-by-step explanation:

Given that

$\int \int Df(x,y)dA=\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy+\int_5^7\int_0^{7-y} f(x,y)dxdy\; \cdots (i)$

For the term $\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy$ .

Limits for $x$ is from $x=0$ to $x=\frac {2y}{5}$ and for $y$ is from $y=0$ to $y=5$ and the region $D$ , for this double integration is the shaded region as shown in graph 1.

Now, reverse the order of integration, first integrate with respect to $y$ then with respect to $x$ . So, the limits of $y$ become from $y=\frac{5x}{2}$ to $y=5$ and limits of $x$ become from $x=0$ to $x=2$ as shown in graph 2.

So, on reversing the order of integration, this double integration can be written as

$\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx\; \cdots (ii)$

Similarly, for the other term $\int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy$ .

Limits for $x$ is from $x=0$ to $x=7-y$ and limits for $y$ is from $y=5$ to $y=7$ and the region $D$ , for this double integration is the shaded region as shown in graph 3.

Now, reverse the order of integration, first integrate with respect to $y$ then with respect to $x$ . So, the limits of $y$ become from $y=5$ to $y=7-x$ and limits of $x$ become from $x=0$ to $x=2$ as shown in graph 4.

So, on reversing the order of integration, this double integration can be written as

$\int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy=\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx\;\cdots (iii)$

Hence, from equations $(i)$ , $(ii)$ and $(iii)$ , on reversing the order of integration, the required expression is

$\int \int Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx+\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx$

$\Rightarrow \int \int Df(x,y)dA=\int_0 ^2\left(\int _ {\frac {5x}{2}}^5 f(x,y)+\int _5 ^ {7-x} f(x,y)\right)dydx$

$\Rightarrow \int \int Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^{7-x} f(x,y)dydx\; \cdots (iv)$

Now, compare the RHS of the equation $(iv)$ with

$\int_a^b\int_{g_1(x)}^{g_2(x)} f(x,y)dydx$

We have,

$a=0, b=2, g_1(x)=\frac{5x}{2}$ and $g_2(x)=7-x$ .

3 0

3 years ago

Seven-tenths of the product of 5p and 3 in algebraic expression

maw [93]

Answer:

$\frac{7}{10}(5p*3)$

Step-by-step explanation:

we know that

The algebraic expression of seven-tenths is equal to the number 7 divided by ten

$\frac{7}{10}$

The algebraic expression of the product of 5p and 3 is equal to multiply 5p by 3

$(5p*3)$

therefore

The algebraic expression of seven-tenths of the product of 5p and 3 is equal to

$\frac{7}{10}(5p*3)$

7 0

4 years ago

1. Scientific Notation and Percent. (Based on the ideas in Objective 1 and Objective 4.) 6 points

vlabodo [156]

Answer: $1.715*10^{12}$ skin cells were not burned.

Step-by-step explanation:

<h3><u> The complete exercise is: Two percent of Sennie's skin cells were burned when she escaped from a fire. If $3.5*10^{10}$ of her skin cells were burned then, how many skin cells were not burned?</u></h3><h3 />

Let be "x" the number of Sennie's skin cells that were not burned when she escaped from the fire.

According the the data given in the exercise, you know that 2% represents $3.5*10^{10}$ of Sennie's skin cells that were burned. This means that the percent of her skin cells that were not burned is:

$100\%-2\%=98\%$

With this information you can write the following proportion:

$\frac{3.5*10^{10}}{2}=\frac{x}{98}$

Solving for "x", you get:

$(98)(\frac{3.5*10^{10}}{2})=x\\\\x=171.5*10^{10}$

To express the result in Scientific notation, the decimal point must be after the first digit; then you must move the decimal point two places to the left:

$x=1.715*10^{12}$

7 0

4 years ago