Based on the calculations, the molar solubility of AgCl in 0. 500 M of NH₃ is equal to 2.77 × 10⁻² M.
<u>Given the following data:</u>
- Ksp of mg(oh)₂ = 1.8 × 10⁻¹⁰
- Concentration of NH₃ = 0.500
- Kf of ag(nh₃)₂⁺ = 1.7 × 10⁷
<h3>How to determine the molar solubility.</h3>
First of al, we would write the properly balanced chemical equation for this chemical reaction:
Ksp = 1.8 × 10⁻¹⁰
Kf = 1. 7 × 10⁷
K = Ksp × Kf
K = 1. 80 × 10⁻¹⁰ × 1.7 × 10⁷
K = 3.06 × 10⁻³
Mathematically, the Ksp for the above chemical reaction is given by:
![K=\frac{ [Ag(NH_3)_2^{+}][Cl]}{[NH_3]^2}\\\\3.06 \times 10^{-3}=\frac{[x][x]}{0.50^{2 }}\\\\3.06 \times 10^{-3}=\frac{x^2}{0.25}\\\\x^2 = 7.65\times 10^{-4}\\\\x=\sqrt{7.65\times 10^{-4}}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%20%5BAg%28NH_3%29_2%5E%7B%2B%7D%5D%5BCl%5D%7D%7B%5BNH_3%5D%5E2%7D%5C%5C%5C%5C3.06%20%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B0.50%5E%7B2%20%7D%7D%5C%5C%5C%5C3.06%20%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7Bx%5E2%7D%7B0.25%7D%5C%5C%5C%5Cx%5E2%20%3D%207.65%5Ctimes%2010%5E%7B-4%7D%5C%5C%5C%5Cx%3D%5Csqrt%7B7.65%5Ctimes%2010%5E%7B-4%7D%7D)
x = 2.77 × 10⁻² M.
Read more on solubility here: brainly.com/question/3006391
Answer:
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If you were the coach, the player I would want on my team would be player A.
<h3>Which player would I want on my team?</h3>
The player I would want on my team is the better player.
Statistics of Player A:
Minimum score = 14
Maxium score = 40
First quartile = 25
Median = 31
Third quartile = 33
Statistics for Player B:
Arranging Player B's scores in ascending order: 8, 21, 22, 22, 25, 25, 26, 28, 29, 31, 32, 35, 46
Minimum score = 8
Maxium score = 46
First quartile = 1/4(13 + 1) = 22
Median = 26
Third quartile = 3/4(13 + 1) = 31.5
Please find attached the complete question. To learn more about median, please check: brainly.com/question/20434777
Answer: ![-2x^2-3x+8](https://tex.z-dn.net/?f=-2x%5E2-3x%2B8)
Explanation:
To find the difference is to subtract the two polynomials.
![3x^2-5x+2-(5x^2-2x-6)](https://tex.z-dn.net/?f=3x%5E2-5x%2B2-%285x%5E2-2x-6%29)
You would distribute the subtraction sign to have an equation where you can add and subtract like terms.
![3x^2-5x+2-5x^2+2x+6](https://tex.z-dn.net/?f=3x%5E2-5x%2B2-5x%5E2%2B2x%2B6)
Now, we combine like terms.
![-2x^2-3x+8](https://tex.z-dn.net/?f=-2x%5E2-3x%2B8)
At one is C a satellite because it moves around Earth