Answer:
The battle involved the largest number of casualties of the entire war and is often described as the war's turning point due to the Union's decisive victory and concurrence with the Siege of Vicksburg.
The 1st row has 15 chairs.
The 2nd row has 15 + 3 = 18 chairs.
The 3rd row has 18 + 3 = 15 + 2•3 = 21 chairs.
The 4th row has 21 + 3 = 15 + 3•3 = 24 chairs.
The pattern continues, so that the n-th row has 15 + (n - 1)•3 = 3n + 12 chairs.
If there are 15 rows, then the total number of chairs is
![\displaystyle \sum_{n=1}^{15} (3n + 12) = 3 \sum_{n=1}^{15} n + 12 \sum_{n=1}^{15} 1 = 3\cdot\frac{15\cdot16}2 + 12\cdot15 = \boxed{540}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5E%7B15%7D%20%283n%20%2B%2012%29%20%3D%203%20%5Csum_%7Bn%3D1%7D%5E%7B15%7D%20n%20%2B%2012%20%5Csum_%7Bn%3D1%7D%5E%7B15%7D%201%20%3D%203%5Ccdot%5Cfrac%7B15%5Ccdot16%7D2%20%2B%2012%5Ccdot15%20%3D%20%5Cboxed%7B540%7D)
where we use the formulas
![\displaystyle \sum_{n=1}^N 1 = N](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5EN%201%20%3D%20N)
![\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5EN%20n%20%3D%20%5Cfrac%7BN%28N%2B1%29%7D2)
Answer:
Framboise.
Would this work?
If it does have a good day
Where’s the table? There is no picture
The correct answer is composite score.
The Composite score is the average of an individual's test scores in four different examinations, adjusted to the closest entire number. Parts short of what one-half are adjusted down; portions one-half or more are gathered together. Examinations may include subjects such as Mathematics, English, Reading and Science.