A) Substitute -6 for where x is in the expression...
g(-6) = 3(-6)^2 + 2(-6) + 5
g(-6) = 3(36) + 2(-6) + 5
g(-6) = 108 + 2(-6) + 5
g(-6) = 108 - 12 + 5
g(-6) = 96 + 5
g(-6) = 101
b) Substitute (p + 2) into where x is...
g(p + 2) = 3(p + 2)^2 + 2(p + 2) + 5
g(p + 2) = 3(p + 2)(p + 2) + 2(p + 2) + 5
g(p + 2) = 3(p^2 + 4p + 4) + 2(p + 2) + 5
g(p + 2) = 3p^2 + 12p + 12 + 2(p + 2) + 5
g(p + 2) = 3p^2 + 12p + 12 + 2p + 4 + 5
g(p + 2) = 3p^2 + 14p + 21
They're equal, if you add the 0 or don't, it's still the same amount
Answer: B pickup truck a to b is 200 in 10secs c to d is 300 in 10secs you drive 40 miles in 20 min then you stop to get gas for 10 min then drive 40 miles back for 20 min.
Step-by-step explanation: cocomelan
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
x-intercept: (9/4,0)
y-intercept: (0,−9)
Okay, so we know a number of students and the amount of girls as a bracket. So what we have to do now is multiply them with each other.
28 *4/7 = 16
So there are 16 girls in Mr. Chang´s class.
You can also determine the boys by - the students with the girls:
28-16=12 boys
Have a nice day :D
