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2 years ago

6

A bug was sitting on the tip of the propeller blade when the propeller started to rotate. The bug held on for 5 rotations before

flying away. How far did the bug travel before it flew off?

1 answer:

Andrej [43]2 years ago

8 0

Answer:

around 1800 full rotations

Step-by-step explanation:

a circle is 360 degrees so if the bug was on it for 5 rotations then it would have traveled 360x5

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What is the absolute deviation for 62 in the data set?

makvit [3.9K]

D is the answer for this question:))

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3 years ago

A triangle is such that the largest angle is three times the smallest angle. Find the measure of each angle

sammy [17]

Let x represent the smallest angle. Then the largest is 3x, and the remaining angle is 180-4x. The problem statement tells us
.. 3x > 180 -4x > x
Adding 4x gives us
.. 7x > 180 > 5x
or
.. 36 > x > 180/7 = 25 5/7

The angles, smallest to largest, are
.. x, 4(45 -x), 3x
where 25 5/7 < x < 36

The angles could be, for example, any of ...
.. 26°, 76°, 78°
.. 30°, 60°, 90°
.. 32°, 52°, 96°
.. 35°, 40°, 105°
and an infinite number of other possibilities.

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3 years ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

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3 years ago

The slope of a line is 1, and the y-intercept is -1. What is the equation of the line written in slope-intercept form?

Scilla [17]

The slope-intercept form is:
y = mx + b
where m = slope, and b = y-intercept.
You need a slope of 1, so m = 1.
You need a y-intercept of -1, so b = -1.
Replace m with 1 and b with -1 in the slope intercept form to get

y = 1x + (-1)

which simplifies to

y = x - 1

3 0

3 years ago

Aubree invests money in an account paying simple interest. She invests $30 and no

Marianna [84]

Answer:

8%

Step-by-step explanation:

$30 divided by 100= 0.3/1%

0.3x8=$2.40

$30+$2.4=32.40

8 0

2 years ago