A = 3. Hope this helps! (Was trying to show the work but I can't take pictures at the moment.)
The complete question is
"which statement is true about the extreme value the given quadratic equation? y = -3x^2 + 12x - 33
Oa. The equation has a maximum value with a y coordinate of -27
Ob. The equation has a minimum value with a y coordinate of -21
Oc. the equation has a minimum value with a y coordinate of -27
Od. The equation has a maximum value with a y coordinate of -21"
The quadratic equation has the extreme value at the vertex with a y-coordinate of -21. so, the correct option is D.
<h3>What is a quadratic equation?</h3>
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
The given quadratic equation is
y=-3x^2+12x-33
x = -b/2a
For the given equation the vertex :
x = -12/2(-3) = 2
The value of y at x = 2 is:
y = -3(2²) + 12(2) - 33
y = -12 + 24 - 33
y = -21
The extreme is the maximum for the given equation.
The correct choice is D.
Learn more about quadratic equations;
brainly.com/question/13197897
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Answer:
t<-25/2
Step-by-step explanation:
move the constant to the right hand side and change the sign
-2t>20+5
add the numbers
-2t>25
20+5=25
divide both sides of the inequality by-2ans flip the inequality sign
t<-25/2
Answer t<-25/2
