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3 years ago

15

Point m,5 lies on the line 5x-y=20

1 answer:

boyakko [2]3 years ago

3 0

Answer:

m = 5

Step-by-step explanation:

Given , x = m, y = 5 (from (m,5) )

5x - y = 20

=> 5m - 5 = 20

=> 5m = 20 + 5

=> 5m = 25

=> m = 25/5

=> m = 5

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Whats 34 times 7 plus 89

Amanda [17]

It comes out to 327!
34 times 7 = 238 + 89 and you finally get 327!
I hope this helps! (:

4 0

3 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

4 years ago

Write the vector v in terms of i and j whose magnitude ||v|| and direction 0 are given. ||v|| = 4, 0 = 315 degree v= (Type your

victus00 [196]

Answer:

v = 2√2i -2√2j

Step-by-step explanation:

v = ||v||·cos(θ)i +||v||·sin(θ)j

v = 4cos(315°)i +4sin(315°)j . . . . . . fill in the numbers

v = 2√2i -2√2j . . . . . . . . . . . . . . . put in desired form

6 0

3 years ago

Express 30 km/h in m/s

n200080 [17]

Given - 30Km/hr

soution,

we know that

1 km = 1000 m

1 hr = 3600 second

Now

30km/hr = 30×1000÷3600

30Km/hr = 8.34 m/s

Answer - 8.34 m/s

5 0

3 years ago

Write an expression to represent the perimeter of a rectangle with the length of x -4 and width of 2x +8

gogolik [260]

Answer:

no clue sorry but hi

Step-by-step explanation:

5 0

3 years ago