You would do 120/300 = p/100 and you would get 40%
![- 6x + 9 = - 3x + 3 \\ 3x = 6 \\ x = 2](https://tex.z-dn.net/?f=%20-%206x%20%2B%209%20%3D%20%20-%203x%20%2B%203%20%5C%5C%203x%20%3D%206%20%5C%5C%20x%20%3D%202)
Substitute x = 2 into y = - 6x + 9
![y = - 6(2) + 9 \\ y = - 12 + 9 \\ y = - 3](https://tex.z-dn.net/?f=y%20%3D%20%20-%206%282%29%20%2B%209%20%20%5C%5C%20y%20%3D%20%20-%2012%20%2B%209%20%5C%5C%20y%20%3D%20%20-%203)
Answer : x = 2, y = - 3
Hope this helps. - M
Answer:
solving the inequality
we get:
Step-by-step explanation:
We need to solve the inequality ![-31>x-48](https://tex.z-dn.net/?f=-31%3Ex-48)
Solving the inequality and finding value of x:
![-31>x-48](https://tex.z-dn.net/?f=-31%3Ex-48)
First we will be switching sides i.e. left hand side will become right hand side and right hand side will become left hand side. In doing so, the inequality sign i.e. > will be reversed and changed with <
![x-48](https://tex.z-dn.net/?f=x-48%3C-31)
Now, for finding value of x, we will be adding 48 on both sides
![x-48+48](https://tex.z-dn.net/?f=x-48%2B48%3C-31%2B48%5C%5Cx%3C17)
The value of x is less than 17 i.e. ![\mathbf{x](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%3C17%7D)
So, solving the inequality
we get:
Answer:
6=-3/4x+(-4)
Step-by-step explanation:
The equation of any straight line, called a linear equation, can be written as: y= mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis. So for the given information you can see that they gave you your slope of -3/4 so you fill that in under the m. The point that would cross the y axis would be -4 because when you think of it on a graph you would see it as (-4 y) and (6 x). When you are writing linear equations you use the form y=mx+b.
Hope this helps
<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
</span>
we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
cos C=[a²+b²-c²]/[2*a*b]---> cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°
applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°
calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°
the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°