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Marizza181 [45]
3 years ago
6

If you were moving at 14mph for 8 miles, how long would it take you to travel the 8 miles?

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer

34 minutes

Step-by-step explanation:

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What is the commom difference in the following arithmetic sequence??
aalyn [17]
Each increases by a certain amount called the common difference

4.4-2.8=1.6
6-4.4=1.6
7.7-6=1.7
hmm, some error
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answer is C
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3 years ago
What is the solution for the equation 5/3b^3-2b^2-5=2/b^3-2
PilotLPTM [1.2K]
I looked it up and it said it was c 
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3 years ago
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1 point
koban [17]

Answer:

She will be charged $180 once lets the account go past 6 months before making a payment.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

T = E + P

In this question:

If she pays within 6 months, she is not charged any interest.

However, if after 6 months she has not paid the balance, she is charged 20% interest for this period.

Barbara financed a new bedroom set at the furniture store for $1,800.

This means that P = 1800

20 percent interest

This means that I = 0.2

How much interest will she be charged once she lets the account go past 6 months?

6 months is half a year, so this is E when T = 0.5

E = P*I*t

E = 1800*0.2*0.5

E = 180

She will be charged $180 once lets the account go past 6 months before making a payment.

3 0
3 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
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